If a substance absorbs energy but its temperature does not change, then the internal potential energy is changing.
Answer:
Time, t = 13.34 seconds.
Explanation:
Given the following data;
Initial velocity, u = 85km/hr to meters per seconds = 85*1000/3600 = 23.61 m/s
Final velocity, v = 45km/hr to meters per seconds = 45*1000/3600 = 12.5 m/s
Acceleration, a = -3 km/hr/sec to meters per seconds square = -3*1000/3600 = -0.833m/s²
To find the time;
Acceleration = (v - u)/t
-0.833 = (12.5 - 23.61)/t
-0.833t = -11.11
t = 11.11/0.833
Time, t = 13.34 seconds.
Weight = mass × gravity
W = 50 kg * 10.5 m/s^2
W = 525 kg * m/s^2 or 525 N
hope this helps :)
Answer:
you need to add more details for us to be able to understand the question thxs
Answer:
Final temperature will be 438.076 K
Explanation:
We have given temperature
Volume ![V_1=V\ and\ V_2=\frac{V}{2}](https://tex.z-dn.net/?f=V_1%3DV%5C%20and%5C%20V_2%3D%5Cfrac%7BV%7D%7B2%7D)
As there is no heat transfer so this is an adiabatic process
For and adiabatic process ![TV^{\gamma -1}=constant](https://tex.z-dn.net/?f=TV%5E%7B%5Cgamma%20-1%7D%3Dconstant)
Here ![\gamma =1.4](https://tex.z-dn.net/?f=%5Cgamma%20%3D1.4)
So ![T_1V_1^{\gamma -1}=T_2V_2^{\gamma -1}](https://tex.z-dn.net/?f=T_1V_1%5E%7B%5Cgamma%20-1%7D%3DT_2V_2%5E%7B%5Cgamma%20-1%7D)
![T_2=\left ( \frac{V_1}{V_2} \right )^{\gamma -1}\times T_1](https://tex.z-dn.net/?f=T_2%3D%5Cleft%20%28%20%5Cfrac%7BV_1%7D%7BV_2%7D%20%5Cright%20%29%5E%7B%5Cgamma%20-1%7D%5Ctimes%20T_1)