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strojnjashka [21]
4 years ago
8

Which of the following occurs as light travels farther from its source?

Physics
2 answers:
Otrada [13]4 years ago
7 0
The answer is A
F<span>ar from the source, photons spread over a larger area. </span>
Aloiza [94]4 years ago
4 0

I believe the answer to be 'Far from the source, photons spread over a larger area.' so option A).

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Four 50-g point masses are at the corners of a square with 20-cm sides. What is the moment of inertia of this system about an ax
deff fn [24]

Answer:

moment of inertia I ≈ 4.0 x 10⁻³ kg.m²

Explanation:

given

point masses = 50g = 0.050kg

note: m₁=m₂=m₃=m₄=50g = 0.050kg

distance, r, from masses to eachother = 20cm = 0.20m

the distance, d, of each mass point from the centre of the mass, using pythagoras theorem is given by

= (20√2)/ 2 = 10√2 cm =14.12 x 10⁻² m  

moment of inertia is a proportion of the opposition of a body to angular acceleration about a given pivot that is equivalent to the entirety of the products of every component of mass in the body and the square of the component's distance from the center

mathematically,

I = ∑m×d²

remember, a square will have 4 equal points

I = ∑m×d² = 4(m×d²)

I = 4 × 0.050 × (14.12 x 10⁻² m)²

I = 0.20 × 1.96 × 10⁻²

I =  3.92 x 10⁻³ kg.m²

I ≈ 4.0 x 10⁻³ kg.m²

attached is the diagram of the equation

7 0
3 years ago
What is Alex Rodriguez nationally
faltersainse [42]
He is American. Alex Rodriguez
3 0
3 years ago
A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha
allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

d=2.2i+cj

While the force applied on the particle is

F=3.2i-3.8 j

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

W=F\cdot d (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85

b)

In this problem, the work done on the particle is

W=4.0 J

The force and displacement are still

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

W=F\cdot d

4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8

c)

In this problem instead, the work done on the particle is negative:

W=-1.8 J

As before, the force and displacement are

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

And so again, we calculate the scalar product between  force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

W=F\cdot d

-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33

7 0
3 years ago
(b) The output current of the generator is 2.0A. The output potential difference (p.d.) of the
Luden [163]

Answer:

P = 22 watts

Explanation:

Given that,

The output power of the generator = 2 a

The output potential difference = 11 V

We need to find the output power of the generator. The formula for the output power is given by :

P=V\times I\\\\P=11\times 2\\\\P=22\ W

So, the output power of the generator is equal to 22 Watts.

8 0
3 years ago
Difinition of gravity
erastovalidia [21]

Answer:

it's all around you and it can't be destroyed

6 0
3 years ago
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