Answer is 4,400,000 kg • m/s
Initial momentum = 2 * m v
so if 1 ball popped out with 2 v momentum would be conserved
but the initial kinetic energy of the two balls is
1/2 m v^2 + 1/2 m v^2 = m v^2
But the kinetic energy of one ball with twice the speed would be
KE = 1/2 m (2 v)^2 = 2 m v^2 thus violating conservation of energy
Answer:
the average acceleration is 8.8 m/s^2
Explanation:
The computation of the average acceleration is shown below;
As we know that
a = (v − u) ÷ t
where
a denotes average acceleration
v denotes the speed at the bottom of the slope
u denotes the speed at down the slop
t denotes time
= (25 - 3) ÷ 2.5
= 8.8 m/s^2
hence, the average acceleration is 8.8 m/s^2