Question

A tennis ball bounces on the floor three times. If each time it loses 11% of its energy due to heating, how high does it rise after the third bounce, provided we released it 4.4 m from the floor?

Answer 1

Answer:

h = 3.10 m

Explanation:

As we know that after each bounce it will lose its 11% of energy

So remaining energy after each bounce is 89%

so let say its initial energy is E

so after first bounce the energy is

$E_1 = 0.89 E$

after 2nd bounce the energy is

$E_2 = 0.89(0.89 E)$

After third bounce the energy is

$E_3 = (0.89)(0.89)(0.89)E$

here initial energy is given as

$E = mgH_o$

now let say final height is "h" so after third bounce the energy is given as

$E_3 = mgh$

now from above equation we have

$mgh = (0.89)(0.89)(0.89)(mgH)$

$h = 0.705H$

$h = 0.705(4.4 m)$

$h = 3.10 m$