Answer: question D is trough
Explanation: I learned this already
Answer:
1st one
identity of the H₂O
When water (H2O) freezes into ice, some of the properties have changed but the identity of the H2O is the same. Explanation; Water can exist in liquid, solid; ice and gaseous state; steam. Freezing occurs when water is continuously cool until it turns to solid ice, water freezes at zero degree Celsius
Hope This Helps
Answer:
Exposure to the Atmosphere
Composition of Rock
Surface area of the rock
Climate
Time
Explanation:
Exposure to the Atmosphere - how much of the rock mass is exposed to the environment affects how quickly the rock will be weathered by that very environment
Composition of Rock - what kind of minerals the rock is made of, how easy it is for those minerals to disintegrate and how quickly the react with water and air.
Surface area of the rock - a rick that has a wider surface or smaller pieces is more exposed than one that is a lump. A larger surface area increases the rate of weathering
Climate - if a rock is an area where there are high temperatures or very low temperatures, the rate of weathering is likely to increase. A similar point can be made about a region that experiences a lot of rain.
Time - the longer the rock is exposed to harsh conditions, the more it will experience weathering
Answer:
It would take the object 5.4 s to reach the ground.
Explanation:
Hi there!
The equation of the height of a free-falling object at any given time, neglecting air resistance, is the following:
h = h0 + v0 · t + 1/2 · g · t²
Where:
h = height of the object at time t.
h0 = initial height.
v0 = initial velocity.
g = acceleration due to gravity (-32.2 ft/s² considering the upward direction as positive).
t = time
Let´s supose that the object is dropped and not thrown so that v0 = 0. Then:
h = h0 + 1/2 · g · t²
We have to find the time at which h = 0:
0 = 470 ft - 1/2 · 32.2 ft/s² · t²
Solving for t:
-470 ft = -16.1 ft/s² · t²
-470 ft / -16.1 ft/s² = t²
t = 5.4 s
The gel has a density similar to that of skin, so very little of the incident ultrasonic wave is lost by reflection.
