All categories

2 years ago

The amplitude of the wave in the picture below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm

Physics

1 answer:

antiseptic1488 [7]2 years ago

8 0

Answer:

1cm

Explanation:

The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.

You might be interested in

The single-pole, single-throw switch is normally wired ? between the source and the load to turn devices on and off.

zzz [600]

In series.

Single-pole and single-throw switch:

A switch with only one input and one output is referred to as a Single Pole Single Throw (SPST) switch. This indicates that it has a single output terminal and a single input terminal.

A single pole, one throw switch functions as an on/off switch in circuits. The circuit is turned on when the switch is closed. The circuit is shut off when the switch is open.

Thus, SPST switches are relatively basic in design.

Circuit for a single-pole, single-throw (SPST) switch

Types:

According to the application, it can be divided into three categories, including:

Simple SPST

(ON)-OFF, Push-to-close, SPST Momentary

ON-(OFF), Push-to-Open, SPST Momentary

Inches Switch SPST

Learn more about terminal here:

brainly.com/question/14236970

#SPJ4

7 0

2 years ago

A carton is given a push across a horizontal, frictionless surface. The carton has a mass m, the push gives it an initial speed

sammy [17]

Answer and Explanation:

Data provided in the question

Carbon mass = m

Initial speed = v_i

Coefficient = μk

Based on the above information, the expressions are as follows

a. By using the energy considerations the expression for the carton moving distance is

As we know that

$Fd = \frac{1}{2} m (v_i^2- v_f^2)$

where,

$v_f = 0$

$F = u_kmg$

$(\mu_kg) d = \frac{1}{2} m v_i^2$

$d = \frac{\frac{1}{2}v_i^2}{\mu_kg}$

$d = \frac{v_i^2}{2 \mu_kg}$

b. The initial speed of the carton if the factor of 3 risen, so the expression is

$v_i^1 = 3v_i$

$d^i = \frac{(3v_i^2)}{2\mu_kg}$

$= \frac{9v_i^2}{2\mu_kg}$

$d^i = 9(d)$

8 0

3 years ago

A 41.0 g marble moving at 2.30 m/s strikes a 25.0 g marble at rest. What is the speed of each marble immediately after the colli

Gre4nikov [31]

Answer:

speed of each marble after collision will be 1.728 m/sec

Explanation:

We have given mass of the marble $m_1=41gram=0.041kg$

Velocity of marble $v_1=2.30m/sec$

Its collides with other marble of mass 25 gram

So mass of other marble $m_2=25gram=0.025kg$

Second marble is at so $v_2=0m/sec$

We have to find the velocity of second marble

From momentum conservation we know that

$m_1v_1+m_2v_2=(m_!+m_2)v$ , here v is common velocity of both marble after collision

So $0.041\times 2.30+0.025\times 0=(0.041+0.025)v$

v = 1.428 m /sec

So speed of each marble after collision will be 1.728 m/sec

6 0

3 years ago

1. How can you explain the sound has energy?<br><br><br>

LenKa [72]

Answer:

Sound energy is produced when an object vibrates. The sound vibrations cause waves of pressure that travel through a medium, such as air, water, wood or metal. Sound energy is a form of mechanical energy.

Explanation:

5 0

3 years ago

If 1495 j of heat is needed to raise the temperature of a 351 g sample of a metal from 55.0°c to 66.0°c, what is the specific he

forsale [732]

The amount of heat needed to increase the temperature of a substance by $\Delta T$ is given by
$Q= mC_s \Delta T$
where m is the mass of the substance, Cs is its specific heat capacity and $\Delta T$ is the increase of temperature.

If we re-arrange the formula, we get
$C_s = \frac{Q}{m \Delta T}$
And if we plug the data of the problem into the equation, we can find the specific heat capacity of the substance:
$C_s = \frac{1495 J}{(351 g)(66.0^{\circ}C-55.0^{\circ}C)}=0.39 J/g^{\circ}C$

6 0

3 years ago

Read 2 more answers