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stellarik [79]
2 years ago
10

The amplitude of the wave in the picture below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm

Physics
1 answer:
antiseptic1488 [7]2 years ago
8 0

Answer:

1cm

Explanation:

The amplitude of a wave is the distance from the center line (in this case the 1 cm marker on the vertical ruler) to the highest or lowest point. For this image the highest point is 2 cm, 2cm-1cm=1cm. The lowest point is 0cm, 1cm-0cm=1cm.

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How do scientists use models to make predictions?
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Answer:

scientists use information about the past to build their climate models. scientists test their climate models by using them to forecast past climates. when scientists can accurately forecast past climates, they can be more confident about using their models to predict future climates.

Explanation:

scientists use information about the past to build their climate models. scientists test their climate models by using them to forecast past climates. when scientists can accurately forecast past climates, they can be more confident about using their models to predict future climates.

3 0
3 years ago
Which of the following is a typical property of an ionic compound
Yanka [14]

The answer is C.

Ionic compounds are those that bring together anions and cations bonded together by ionic bonds. The electrostatic forces of the different charges are significant in the bonds that make them strong hence require high energy to break them (high melting point).  Due to the regular structure of ionic compound that tend to form lattices in solid form, when struck, they shatter along the lines of weakness of the lattice.  

6 0
3 years ago
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A light bulb dissipates 100 Watts of power when it is supplied a voltage of 220 volts.
ycow [4]

Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

Answer:

a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

P = VI

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

I = \frac{P}{V}  \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

V = IR

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega

Therefore, the resistance of the bulb is 484 Ω

3 0
3 years ago
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Q) A farmer moves along the boundary of a
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The answer will be 8 because kedks
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3 years ago
How is the frequency of an electromagnetic wave related to energy
aivan3 [116]

Answer: The energy carried by an electromagnetic wave is proportional to the frequency of the wave.  

Explanation:

Electromagnetic waves that are of higher energy than visible light (higher frequency, shorter wavelength) include ultraviolet light, X-rays, and gamma rays.

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3 years ago
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