The question as presented is incomplete, here is the complete question with the multiple choice:
The sequence a1 = 6, an = 3an − 1 can also be
written as:
1) an = 6 ⋅ 3^n
2) an = 6 ⋅ 3^(n + 1)
3) an = 2 ⋅ 3^n
4) an = 2 ⋅ 3^(n + 1)
The correct choice is option 3) an = 2⋅3^n.
If we look at the initial sequence an = 3⋅an-1, and
a1 = 3⋅a0 = 6
a0 = 6/3
a0 = 2
We can now look at the sequence.
a0 = 2
a1 = 6
a2 = 18
a3 = 54
etc...
A common factor in each of those numbers is 2, so we can rewrite the sequence by factoring out 2.
a0 = 2⋅1
a1 = 2⋅3
a2 = 2⋅9
a3 = 2⋅27
The numbers being multiplied by 2 are all factors of 3. So we can rewrite the sequence again as:
a0 = 2⋅3^0
a1 = 2⋅3^1
a2 = 2⋅3^2
a3 = 2⋅3^3
This sequence can now be rewritten as an = 2⋅3^n.
We have been given that function 
is a transformation of the quadratic parent function 
. We are asked to find the y-intercept of function g.
We know that the function is an upward opening parabola with vertex at point (0,0).
We know that vertex form of a parabola is in form 
, where point (h,k) represents vertex of parabola.
We can rewrite g(x) as:
The vertex of the function g(x) is at point (0,2).
We know that the vertex of a function is the point, when x is equal to 0. Therefore, the y-intercept of the g is at (0,2).
Answer:
The function 
is continuous for all real numbers
Step-by-step explanation:
To know the possible points of discontinuity of this function, we must find out when the denominator of the function is equal to 0.
The denominator is:
Then we equal 0 and clear x
for any real number.
This means that
<em>for all reals numbers</em>.
Therefore, the function is <em>continuous</em> for all real numbers, that is, it does not have discontinuities.
The graphic of this function is shown in the image
