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2 years ago

5

What are complex information systems that support end-to-end business processes? Functional systems Accounting systems Enterpris

e systems Management systems

1 answer:

Cloud [144]2 years ago

4 0

Answer:

Enterprise systems

Explanation:

Enterprise Resource planning (ERP) system has enterprise -wide integration and it is integrated end to end business departments and Business units. It interconnects different business segment or department. It helps a department / segment of business to support other departments / segments of the business.

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The fact that the equilibrium quantity of loanable funds may increase along with an increase in the real rate of interest A. ass

joja [24]

Answer:A. assumes that demand for loanable funds increases with supply remaining unchanged

Explanation:

Loanable funds is the sum total of all the money people and entities in an economy have decided to save and lend out to borrowers as an investment rather than use for personal consumption. ... One way to make an investment is to lend money to borrowers at a rate of interest.

7 0

3 years ago

A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius

anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

$T^2 \alpha a^3$

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 $\times 10^8 \ km$

Therefore, $T^2 = ca^3$

$c= \dfrac{365^2}{(1.496 \times 10^8)^3}$

c = 3.9791 $\times 10^{20} \ day^2/km^3$

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

$T^2 = ca^3$

$a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}$

$a^3 = 2.9092 \times 10^{27}$

$a= \sqrt[3]{2.9092 \times 10^{27}}$

a = 1.4275 $\times 10^9 \ km$

However, the velocity for a perihelion = 10.18 km/s

Using the formula

$v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})}$ to calculate the radius, we have:

G = $6.674 \times 10^{-11}$

M = $1.989\times 10^{30} \ kg$

r = perihelion

$v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})$

$(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30} ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})$

$7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}$

$\dfrac{2}{r} = 1.4824 \times 10^{-12}$

$r = \dfrac{2}{1.4824 \times 10^{-12}}$

$r = 1.349 \times 10^{12}$

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

$1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)$

$1.349 \times 10^{12} - 1.425 \times 10^{12}= - 1.425 \times 10^{12} (e)$

$-7.6\times 10^{10}= - 1.425 \times 10^{12} (e)$

$\dfrac{-7.6\times 10^{10}}{- 1.425 \times 10^{12}}= (e)$

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

$r = 1.425 \times 10^{12} ( 1 + 0.0533)$

$r = 1.50 \times 10^{12} \ m$

to nautical miles, we have:

$r = 1.50 \times 10^{12} \times 0.00054 \ nautical \ mile$

radius of aphelion $\mathbf{r = 8.10 \times 10^8}$ nautical miles

In respect to the value of a( i.e $1.4275 \times 10^9 \ km)$

the body of the solar system is Saturn

5 0

3 years ago

Tyler Tooling Company uses a job order cost system with overhead applied to products on the basis of machine hours. For the upco

inessss [21]

Answer:

<u>Over Applied Overhead = $ 4000</u>

Actual Manufacturing Overhead = $45,000

Manufacturing Overhead Applied = $ 49,000

Explanation:

Job 101 Job 102 Job 103

Total Direct materials $ 19,200 $ 14,400 $ 9,600 $ 43,200

Direct labor $ 28,800 $ 11,200 $ 9,600 $ 49,600

Machine hours 1,000 hrs 4,000 hrs 2,000 hrs 7,000 hours

<u>Manufacturing overhead $ 7000 $ 28,000 14,000 </u>

<u>Total $ 55,000 53,600 33,200</u>

Actual overhead costs recorded during the first month of operations totaled $45,000.

<u>Journal Entries </u>

<u>Sr. No Particulars Debit Credit</u>

Job 102 Finished Goods 53,600

Work In Process 53,600

A journal entry showing the transfer of Job 102 into Finished Goods Inventory upon its completion.

Job 101 Sales 60,000

Cost Of Goods Sold 60,000

Journal entries to recognize the sales revenue and cost of goods sold for Job 101.

Job 101 Cost of Goods Sold 55,000

Finished Goods Inventory 55,000

Manufacturing Overhead Applied = $ 7000 + $ 28,000+14,000 = $ 49,000

Job 101 = 1000/60,000 * $ 420,000= $ 7000

Job 102 = 4000/60,000 * $ 420,000= $ 28000

Job 103 = 2000/60,000 * $ 420,000= $ 14000

Actual Manufacturing Overhead = $45,000

<u>Over Applied Overhead = $ 4000</u>

Manufacturing Overhead Accounts $ 4000 debit

Cost of Goods Sold $ 4000 Credit

Entry to transfer the balance of the Manufacturing Overhead account to Cost of Goods Sold.

(Entry to reduce the amount of Over applied Overhead)

6 0

3 years ago

maxonik [38]

d. time period and b. internal factors

5 0

2 years ago

Read 2 more answers

Financial data for Joel de Paris, Inc., for last year follow:

Anon25 [30]

Answer:

Operating profit margin = operating profits ÷ turnover

= 405000 ÷ 4,050,000

= 0.1 = 10%

ROI = Net operating Income/ Average Operating assets

= 405,000 ÷ 1620,000

= 0.25 = 25%

(note: Average operating assets = ( opening operating assets + closing operating assets ) ÷ 2 )

Turnover = sales/ average operating assets

= 4,050,000/ 1620,000

= 2.5

Residual income

minimum required return = minimum required rate of return × average operating assets

= 15% × 1620000

= 243000

Residual income = net operating income - minimum required return

= 162000

8 0

3 years ago