7^5 • 7^6 as a single exponent

Un camión admite en su interior 68,25 toneladas de patatas. Se cada caja de patatas pesa 22,75 Kg, ¿cuántas cajas de

hoa [83]

Answer:

El camión lleva 3000 cajas de patatas

Step-by-step explanation:

Proporciones

La capacidad de carga de un camión es de 68.25 Toneladas de patatas.

Como 1 tonelada es equivalente a 1000 Kg, expresamos la capacidad en Kg:

68.25 * 1000 = 68250 Kg

Cada caja de patatas pesa 22.75 Kg, luego el número de cajas que caben en el camión son:

68250/22.75 = 3000 cajas

El camión lleva 3000 cajas de patatas

6 0

3 years ago

Find a polynomial of degree 3 with real cofficients and zeros of -3,-1,4 for which f(-2)=24

konstantin123 [22]

$\bf \textit{zeros at } \begin{cases} x = -3\implies &x+3=0\\ x = -1\implies &x+1=0\\ x = 4\implies &x-4=0 \end{cases}\qquad \implies (x+3)(x+1)(x-4)=\stackrel{y}{0} \\\\\\ (x^2+4x+3)(x-4)=0\implies x^3~~\begin{matrix}+ 4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~+3x~~\begin{matrix} -4x^2 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~-16x-12=0 \\\\\\ x^3-13x-12=0$

we know that f(-2) = 24, namely when x = -2, y = 24, let's see if that's true

$\bf x^3-13x-12=y\implies \stackrel{x = -2}{(-2)^3-13(-2)-12}=y \\\\\\ -8+26-22=y \implies 6=y$

darn!! no dice.... hmmmm wait a second.... 4 * 6 = 24, if we could just use a common factor of 4 on the function, that common factor times 6 will give us 24, let's check.

$\bf 4(x^3-13x-12)=y\implies \stackrel{x = -2}{4[~~(-2)^3-13(-2)-12~~]}=y \\\\\\ 4[~~-8+26-22~~]=y\implies 4[6]=y\implies 24=y \\\\[-0.35em] ~\dotfill\\\\ ~\hfill 4x^3-52x-48=y~\hfill$

4 0

3 years ago

Drug X is to be administered intravenously at a dosage of 20 mg/kg. A patient weighing 60 kg should receive

arsen [322]

Answer:

D. 1200 mg

Step-by-step explanation:

In order to find the solution we need to understand that a dosage of 20 mg/kg means that 20 mg are administered to the patient for each kg of his/her weight.

So, if the patient weight is 60 kg then:

Total drug X = (20mg/Kg)*(60Kg)=1200mg.

In conclusion, 1200 mg will be administered to the patient, so the answer is D.

5 0

2 years ago

The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh

sp2606 [1]

<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

Solution:

Given that,

The height of a ball thrown into the air after t seconds have elapsed is:

$h = -16t^2 + 40t + 6$

What is the first time, t, when the ball will reach a height of 20 feet?

Substitute h = 20

$20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0$

Solve by quadractic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-20,\:c=7$

$t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084$