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alisha [4.7K]
2 years ago
8

Martha and sarah leave block p and q towards q and p respectively simultaneously and travel in the same route. After meeting eac

h other on the way, sarah takes 3 hours to reach her destination, while martha takes 5 hours to reach her destination. If the speed of sarah is 40 km/hr, what is the average speed of martha and sarah?.
Mathematics
1 answer:
olga_2 [115]2 years ago
5 0

The average speed of Martha and Sarah is 32 km/h.

We need to know about the speed to solve this problem. Speed can be determined as the distance traveled divided by time. It can be written as

v = s / t

where v is speed, s is distance and t is time.

From the question above, we know that:

t sarah = 3 hours

t martha = 5 hours

v sarah = 40 km/h

By using the speed equation, we get the distance

vsarah = s / tsarah

40 = s/3

s = 120 km

Find Martha's speed

vmartha = s / tmartha

vmartha = 120 / 5

vmartha = 24 km/h

Find average speed

v = (vsarah + vmartha)/2

v = (40 + 24) / 2

v = 32 km/h

Hence, the average speed of Martha and Sarah is 32 km/h.

Find more on speed at: brainly.com/question/6504879

#SPJ4

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For practical purposes we will think that every couple is healthy enough to give birth as much children needed until giving birth a girl.

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Observe that statement 1 implies that:

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\sum^{\infty}_{n=1}(n-1)P(B_{n-1})=\sum^{\infty}_{n=1}(n-1)(\frac{1}{2} )^n=\sum^{\infty}_{n=2}n(\frac{1}{2} )^n=\\\\=\sum^{\infty}_{m=2}\sum^{\infty}_{n=m}(\frac{1}{2} )^n=\sum^{\infty}_{m=2}(\frac{1}{2} )^{m-1}=\sum^{\infty}_{m=1}(\frac{1}{2} )^{m}=1.\\

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Step-by-step explanation:

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