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finlep [7]
3 years ago
11

Write a balanced equation for the combustion of liquid methanol in air, assuming H2O(g) as a product.

Chemistry
1 answer:
pentagon [3]3 years ago
7 0

Answer:

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

Explanation:

Methanol is CH₃OH.  Oxygen is O₂.  A combustion produces CO₂ and H₂O.  Create an equation using this information and balance.

CH₃OH  +  O₂  ⇒  CO₂  +  H₂O

2 CH₃OH  +  3 O₂  ⇒  2 CO₂  +  4 H₂O

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58.0 g of K2SO4 was dissolved in 500 g of water. What is the molality of this solution?
podryga [215]

Answer: The molality of solution is 0.66 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molarity=\frac{n\times 1000}{W_s}

where,

n = moles of solute

W_s = weight of solvent in g

moles of K_2SO_4 = \frac{\text {given mass}}{\text {Molar Mass}}=\frac{58.0g}{174g/mol}=0.33mol

Now put all the given values in the formula of molality, we get

Molality=\frac{0.33\times 1000}{500g}=0.66mole/kg

Therefore, the molality of solution is 0.66 mole/kg

7 0
3 years ago
A cup of hot water loses 265 cal
elixir [45]

Answer:

-1071 Joules

Explanation:

The Joule was introduced as the SI unit for energy in 1925.  One calorie is equal to approximately 4.184 joules(J).  This is a conversion factor that we can write two ways:

(1cal/4.184J) or (4.184J/1cal)

(265 cal)*(4.184J/1cal) = 1071 J

Since the energy is leaving the system, it should be written with a minus sign:  -1071J

7 0
2 years ago
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Answer:

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Explanation:

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