Answer:
56
Step-by-step explanation:
Complete question:
Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)
If z varies jointly with x, and y, this is expressed as;
z = kxy
If z=7 when x= 2, y= 2
7 = k(2)(2)
7 = 4k
k = 7/4
To get z when x= 4 and y = 8
z = kxy
z =7/4 (4)(8)
z = 7*8
z = 56
Hence the value of z is 56
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Step-by-step explanation:
Answer:
Length = 27 metresWidth = 9 meters
Step-by-step explanation:
Answer:
STEP 1: Find the circumference:
Circumference = 2πr
Circumference = 2π(14) = 28π cm
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STEP 2: Find the length of the arc:
Length of the arc = 36/360 x 28π
Length of the arc = 8.8 cm
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Answer: The length of the arc is 8.8 cm
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hope it helpssss
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Let's begin by evaluating f(x) using the value of 3: f(x) = 2x2 - 4x - 4 (original function) f(3) = 2(3)2 - 4(3) - 4 (plugging in 3 for x) f(3) = 2 (computed result) Now let's evaluate g(x) using the value of 3: g(x) = 4x - 7 (original function) g(x) = 4(3) - 7 (plugging in 3 for x) g(x) = 5 (computed result) Finally, we'll sum our results: (f + g)(3) = 2 + 3 (add f(3) and g(3)) <span>(f + g)(3) = 5 (final answer)</span>