Answer:
100
Step-by-step explanation:
it is a bit unclear to me, what that problem description means.
if I understand it correctly, than z is directly depending on x².
so, z = 16 for x = 2. x² = 4
I pondered a little bit, as there are several possibilities to connect 16 with 4 as a driving factor (e.g. 2⁴ = 16, 4×4 = 16, 12 + 4 = 16).
I decided to go with the simplest interpretation with the usual meaning of "varies" (multiplication) : 4×x²
that would mean
z = 4×x² = 4×5² = 4×25 = 100
3x - 4 + x^2 - 1 + 2x^2 - 15
3x^2 + 3x - 20
I wasn't sure if you wanted me to solve for x, but I did anyways.
x ≈ 1.86, or -2.86
Hey there!
Let's break this expression into two parts:
6(3x-1) and -10x
To solve the first part, we need to use the distributive property which states:
a(b+c) = ab+ac
Applying that to this problem, we have:
6(3x) + 6(-1) =
18x - 6
Now, we can take that -10x and put it right back in:
18x - 6 - 10x
Combine like terms and subtract the 10x from the 18x to get:
8x - 6
Hope this helps!
Congruent since all angles are equivalent to each other.
When roots of polynomials occur in radical form, they occur as two conjugates.
That is,
The conjugate of (a + √b) is (a - √b) and vice versa.
To show that the given conjugates come from a polynomial, we should create the polynomial from the given factors.
The first factor is x - (a + √b).
The second factor is x - (a - √b).
The polynomial is
f(x) = [x - (a + √b)]*[x - (a - √b)]
= x² - x(a - √b) - x(a + √b) + (a + √b)(a - √b)
= x² - 2ax + x√b - x√b + a² - b
= x² - 2ax + a² - b
This is a quadratic polynomial, as expected.
If you solve the quadratic equation x² - 2ax + a² - b = 0 with the quadratic formula, it should yield the pair of conjugate radical roots.
x = (1/2) [ 2a +/- √(4a² - 4(a² - b)]
= a +/- (1/2)*√(4b)
= a +/- √b
x = a + √b, or x = a - √b, as expected.
