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ruslelena [56]
3 years ago
8

Z varies jointly with x, and y, and z=7 when x= 2, y= 2

Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

56

Step-by-step explanation:

Complete question:

Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)

If z varies jointly with x, and y, this is expressed as;

z = kxy

If z=7 when x= 2, y= 2

7  = k(2)(2)

7 = 4k

k = 7/4

To get z when x= 4 and y = 8

z = kxy

z =7/4 (4)(8)

z = 7*8

z = 56

Hence the value of z is 56

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Which shows two products that result in negative values​
Zanzabum

Answer:

(2.4)(-1.8) and (0.6)(-0.4)

Step-by-step explanation:

The product of two negative numbers = a positive number. (negative × negative = positive).

Product of two positive numbers = a positive number. (Positive × positive = positive)

Product of a negative number and a positive number = a negative number. (Negative × positive = negative).

Therefore, the answer choice that shows two products that both will result in negative values would be the answer choice that has a negative number multiplying a positive number.

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Therefore, the answer is Option 3: (2.4)(-1.8) and (0.6)(-0.4)

5 0
4 years ago
Which equations represent the line that is perpendicular to the line 5x – 2y = -6 and passes through the point
natta225 [31]

Answer: 2x + 5y = - 10, Cy + 4 = (x-5)

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Step-by-step explanation:

Equation of the line

5x - 2y = -6

Conditions for perpendicularity

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To get m1, rearrange the equation

2y = 5x + 6

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4 0
3 years ago
Read 2 more answers
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