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Vedmedyk [2.9K]
3 years ago
13

Is it just me, or does the my pillow ad play on every other break on tv

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

Yes..

Step-by-step explanation:

every old TV channel you see a glitchy my pillow ad

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The following data points represent the number of players on the Russian Bears volleyball team that were injured in each match t
zvonat [6]

Answer:

its 0=0 1=3 and 2=3

Step-by-step explanation: count how many of the injuries there are for 0. In this case there is none. so how many 1's are there, 3. so put 3 in 1. Now two there is 3 for 2 so put 3 in the 2.

5 0
3 years ago
Which equation represents the circle described?
bazaltina [42]

We have the equation:

x^2+y^2-8x-6y+24=0


By arranging this equation in terms of x and y, we have:


x^2-8x+y^2-6y=-24 \\ \\


By using the method of completing the square, we have:

x^2-8x+\mathbf{\left(\frac{8}{2}\right)^2}+y^2-6y+\mathbf{\left(\frac{6}{2}\right)^2}=-24+\mathbf{\left(\frac{8}{2}\right)^2}+\mathbf{\left(\frac{6}{2}\right)^2} \\ \\ x^2-8x+\mathbf{16}+y^2-6y+\mathbf{9}=-24+\mathbf{16}+\mathbf{9} \\ \\ \boxed{(x-4)^2+(x-3)^2=1}


The center of this circle is:

(h,k)=(4,3)


So the equation that fulfills the statement is:

(x-4)^2+(y-3)^2=2^2


Finally, the right answer is c)

6 0
3 years ago
Read 2 more answers
A and b are positive integers and a–b = 3. Evaluate the following: 27^ (1/3 b)/9^ (1/2 a)
maxonik [38]

Answer:

1/27

Step-by-step explanation:

27^(b/3)/9^(a/2) = (27^(1/3))^b/(9^(1/2))^a = (3^b)/(3^a) = 3^(b-a)

= 3^(-(a-b)) = 3^-3 = 1/3^3 = 1/27

5 0
3 years ago
Taka conducts an experiment where he rolls a number cube, with sides labeled from 1 to 6, and then flips a coin. This table show
sweet [91]
The experimental probability is 1/6, and the theoretical probability is 1/4. The theoretical probability is greater than the experimental probability in this trial.-------------------Explanation:
Theoretical probability is the mathematically calculated probability of the circumstances occurring. 
There is a 1/2 chance of rolling an even number, and a 1/2 chance of flipping a coin on heads.
Since the question asks for the possibility of both happening, multiply those together to find the probability:


The theoretical probability of rolling an even number and then flipping a head is 1/4.
Now we'll focus on Taka's trials.
Experimental probability is the probability that is taken from results of a trial.
Take the results, and see if they match the criteria of rolling an even number and flipping heads.
The results that are bolded fit the criteria:1 H, 4 T, 1 H, 5 T, 2 H, 3 T, 6 T, 2 H, 3 T, 5 T, 3 H, 4 T
Taka managed to roll and flip the coin to fit the criteria 2 times out of 12. Converted into a fraction, it is 2/12. Simplified, the experimental probability is 1/6
7 0
3 years ago
15. Divide the polynomial x^3 + x^2 - 2x + 3 by (x - 1).​
Stels [109]

Answer:

x² + 2x + [3\x - 1]

Step-by-step explanation:

Since the divisor is in the form of <em>x - c</em>, use what is called <em>Synthetic Division</em>. Remember, in this formula, -c gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:

1| 1 1 -2 3

↓ 1 2 0

------------------

1 2 0 3 → x² + 2x + [3\x - 1]

You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + 5x - 36]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder, which in this case is a 3, so what you is set the divisor underneath the remainder of 3. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x², 2 becomes <em>2x</em><em>,</em><em> </em>and the remainder of 3 is set over the divisor, giving you the other factor of <em>x² + 2x + [3\x - 1]</em>.

If you are ever in need of assistance, do not hesitate to let me know by subscribing to my channel [USERNAME: MATHEMATICS WIZARD], and as always, I am joyous to assist anyone at any time.

5 0
3 years ago
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