Equivalent expression of 8x+12-x

According to government data, 75% of employed women have never been married. Rounding to 4 decimal places, if 15 employed women

blagie [28]

Answer:

We are given that According to government data, 75% of employed women have never been married.

So, Probability of success = 0.75

So, Probability of failure = 1-0.75 = 0.25

If 15 employed women are randomly selected:

a. What is the probability that exactly 2 of them have never been married?

We will use binomial

Formula : $P(X=r) =^nC_r p^r q^{n-r}$

At x = 2

$P(X=r) =^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=2) =\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{13}$

$P(X=2) =8.8009 \times 10^{-7}$

b. That at most 2 of them have never been married?

At most two means at x = 0 ,1 , 2

So, $P(X=r) =^{15}C_0 (0.75)^0 (0.25^{15-0}+^{15}C_1 (0.75)^1 (0.25^{15-1}+^{15}C_2 (0.75)^2 (0.25^{15-2}$

$P(X=r) =(0.75)^0 (0.25^{15-0}+15 (0.75)^1 (0.25^{15-1}+\frac{15!}{2!(15-2)!} (0.75)^2 (0.25^{15-2})$

$P(X=r) =9.9439 \times 10^{-6}$

c. That at least 13 of them have been married?

P(x=13)+P(x=14)+P(x=15)

$={15}C_{13}(0.75)^{13} (0.25^{15-13})+{15}C_{14} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=\frac{15!}{13!(15-13)!}(0.75)^{13} (0.25^{15-13})+\frac{15!}{14!(15-14)!} (0.75)^{14}(0.25^{15-14}+{15}C_{15} (0.75)^{15} (0.25^{15-15})$

$=0.2360$

8 0

3 years ago

prove or disprove that if you have an 8-gallon jug of water and two empty jugs with capacities of 5 gallons and 3 gallons, respe

Serjik [45]

Answer:

We can measure 4 gallon by successively.

Step-by-step explanation:

We have been given that you have an 8-gallon jug of water and two empty jugs with capacities of 5 gallons and 3 gallons, respectively. We are asked to prove or disprove that you can measure 4 gallon by successively pouring some of or all of the water in a jug into another jug.

First of all, we will pour 5 gallons of water from 8 gallon jug. Then we will pour 5 gallons of water from 5 gallon jug to 3 gallon jug. That will result in 2 gallons of water in 5 gallon jug.

Now, we will pour 3 gallons of water from 3 gallon jug to 8 gallon jug and pour 2 gallons from 5 gallon jug into 3 gallon jug. That will give us 6 gallons in 8 gallon jug and 2 gallons in 3 gallon jug and empty 5 gallon jug.

In our last step, we will fill 5 gallons jug from 8 gallon jug. After filling 5 gallon jug, we will fill 3 gallons jug from 5 gallon jug. Since 3 gallon jug already contains 2 gallons water, so it can only take one more gallon.

After pouring one gallon from 5 gallon jug, we will get 4 gallons water in 5 gallon jug.

Therefore, we can measure 4 gallon by successively pouring some of the water in a jug into another jug.

4 0

3 years ago

A dollar bill is worth _____ pennies. When written in decimal format, each penny can be written as ______ of a dollar. 100:10 10

erik [133]

Hey there! :D

A dollar bill is worth 100 pennies.

$1.00-> .01*100 <=== same thing

When written in decimal format, each penny can be written as 100:1, because there are 100 pennies in a dollar. One penny would just be one out of 100.

I hope this helps!
~kaikers

5 0

3 years ago

Read 2 more answers

I NEED THIS BADLY <br> WILL MARK BRAINLYIST

stiks02 [169]

What’s the question?

5 0

2 years ago

At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m

Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

$\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30$

Thus, 99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

3 0

3 years ago