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3 years ago

A student scored 80 points in an exams,the teacher took off 5% off for lateness,what will be the student's final score

1 answer:

6 0

Awesome question!

1.) You have 80 points and you want to take away 5% of them.

- 5% is 1/2 of 10%. And remember your number places. So 80 has 0 in the ones and an 8 in the tens place. Move the decimal over to the left 1 time and you get 8.00 Now you have 10% of 80. And 5% is one half of 10%, so 8/2 is 4.

4 is 5% of 80. And you take away 4 from 80 and end up with 76.

Hope I explained this for ya!

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3 years ago

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Liono4ka [1.6K]

Answer:

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2 years ago

Read 2 more answers

22. Determine the value of c so that the line

tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints D(c, -7) and E(5, -3).

Using slope formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$ we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

$\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}$

We have:

$x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \$

Putting values and finding c

$\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2$

So, If the lines BC and DE are parallel, the value of c is c=-2

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3 years ago

Find the value of the variable

WINSTONCH [101]

Which variable are you talking about? In this question x is 4 and y is 5.

Hope this helped!

Good Luck!

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2 years ago

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Virty [35]

Answer: A) 10
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3 years ago