Answer:
-32 and -33
Step-by-step explanation:
x + (x + 1) = -65
2x +1 = -65
2x = -66
x = -33. So (x + 1) = -33 + 1 = -32
-33 + -32 = -65
Answer:
4.4 ≤ x
Step-by-step explanation:
2/5 ≤ x -4
solve using inverse operations:
2/5 ≤ x - 4
0.4 ≤ x - 4
+4 +4
4.4 ≤ x
Rational zero theorem is all combinations of p(factors of the constant) divided by q(factors of the first coefficient)
factors of 8 are 1, 2, 4, 8
factors of 2 are 1, 2
so all possible rational zeros are all combinations of p/q
+/- 1/1, 1/2, 2/1, 2/2, 4/1, 4/2, 8/1, 8/2
Now there are some repeats in there so you have to leave those out and once we do that we get
+/- 1, 1/2, 2, 4, 8
Remember all those are plus OR minus
First join the log4 on the left:
log4( x*(x-3) = log4(-7x+21)
Then x = -7, works: -7*(-10)=70 = -7*(-7)+21
x=-3, 18 = 42, does not work
x=3 0=0 works,
However, when one puts x = -7 in the *original* exression, log4(-7) or log4(-10) do not exist (you know why?). So x= -7 is extraneous.
Now x=3 gives log4(0) on the left and right, which does not exist.
So, C is the answer, both are extraneous. Seem to work but indeed don't work in the *original* equation
45 and 105, you can put the equation as 3x+7x=150. Add them to 10x then divide, x=15 so 3*15=45, and same for the other number.
