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3 years ago

Solve x squared + 5x +6 = 0

Mathematics

2 answers:

ipn [44]3 years ago

7 0

Answer:

x = -2 and x = -3

Step-by-step explanation:

<h2>Solving for the value of (x)</h2>

$x^{2} + 5x + 6 =0\\$

we can make use of the product and sum method

sum is the second term , 5

product is the third term , 6

the two values when added is 5 and when multiplied is 6

is : (2,3)

when 2 and 3 is multiplied is = 6

when 2 and 3 is added is = 5

(x +2)(x + 3) = 0

x+2 = 0

hence x = -2

(x + 3) = 0

x + 3 =0

hence x = -3

alina1380 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

Move all terms that don't contain xx

to the right side and solve.

Exact Form:x=−65x=-65

Decimal Form:x=−1.2x=-1.2

Mixed Number Form:x=−115x=-115

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If a_1=9a

pickupchik [31]

A geometric series is the collection of an unlimited number of terms with a fixed ratio between them. The value of a₅ is -729.

<h3>What is geometrical series?</h3>

A geometric series is the collection of an unlimited number of terms with a fixed ratio between them.

Given the value of a₁=9 and the value of $a_n=-3a_{(n-1)}$ . Therefore, the value of a₅ can be written as,

a₂ = -3(a₁) = -3(9) = -27

a₃ = -3(a₂) = -3(-27) = 81

a₄ = -3(a₃) = -3(81) = -243

a₅ = -3(a₄) = -3(-243) = -729

Hence, the value of a₅ is -729.

Learn more about Geometrical Series:

brainly.com/question/4617980

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2 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

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If a triangle has lengths of 3ft and 54ft, check ALL possible lengths for the third side 51ft 53ft 55ft 57ft 58ft

ra1l [238]

Answer:

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Step-by-step explanation:

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