Answer:
The speed and direction of the two players immediately after the tackle are 3.3 m/s and 53.4° South of West
Explanation:
given information:
mass of fullback, = 92 kg
speed of full back, = 5.8 to south
mass of lineman, =110 kg
speed of lineman, = 3.6
according to conservation energy,
assume that the collision is perfectly inelastic, thus
initial momentum = final momentum
= '
m₁v₁ = (m₁+m₂)'
' = m₁v₁/(m₁+m₂)
= (92) (5.8)/(92+110)
= 2.64 m/s
= '
m₂v₂ = (m₁+m₂)'
' = m₁v₁/(m₁+m₂)
= (110) (3.6)/(92+110)
= 1.96 m/s
thus,
' = √'²+'²
= 3.3 m/s
then, the direction of the two players is
θ = 90 - tan⁻¹('/')
= 90 - tan⁻¹(1.96/2.64)
= 53.4° South of West
<span>Magnetic field lines form circles that go around the wire.</span>
Answer:
a) S = 24.4 m/s
b) angle from the +y direction = 28.7°
Explanation:
1) Data
Vy = 21.4 m/s = constant
Vy,o = 0
Ax = 0.301 m/s²
t = 38.9 s
a) V = ?
b) angle=?
2) Formulas
i) Vy = constant = Vy,o
ii) Vx = Vx,o + Ax t = 0 + Ax t = Ax t
3) Solutions
a) speed
t = 38.9 s and Vx,o = 0.301 m/s² ⇒ Vx = 0.301 m/s² × 38.9s = 11.7 m/s
V² = Vx² + Vy² = (11.7 m/s)² + (21.4m/s)² = 594.85 m² / s²
⇒ V = 24.39 m/s
b) angle measured from the +y direction
tan (angle) = Vx/Vy = 11.7 m/s / 21.4 m/s = 0.5467
angle = arctan(0.5467) ≈ 28.7°
Answer: The satellite, if it is orbiting at a certain speed once launched into space, will continue to orbit at that same speed until it collided with some other force, such as debris or something along those lines. In space, with the amount of gravitational pull that surrounds the earth, once something falls into orbit, it will continue to orbit the same way as it began. The earth will continue to pull the satellites towards itself with the same amount of force, and so will keep its orbit consistent.
Explanation: