Answer-C VO2-Q2/2C-I2R=0
Q1/2C currents upon the charge I2R on the capacitor. Voltage V02 goes best
Answer:
18.032m/s, 16.59m
Explanation:
Used to find the distance traveled
y=1/2gt^2, where y= vertical distance, g=acceleration due to gravity, and t=time
y=1/2*9.8*1.84^2
y=16.59m distance
Used to solve the final velocity before hitting the ground
vf=vo+at where vf=final velocity, vo=initial velocity, a=acceleeration, t=time
vf=0+9.8*1.84
vf=18.032m/s
The first one because the temperature of the water outside is higher than the one on the inside therefore the one on the inside is heating up
water vapor that has condensed and covers the ground in the morning
Answer:
72 m
Explanation:
Given:
v₀ = 0 m/s
v = 60 m/s
a = 25 m/s²
Find: Δx
v² = v₀² + 2aΔx
(60 m/s)² = (0 m/s)² + 2 (25 m/s²) Δx
Δx = 72 m