Remember that density refers to the "mass per unit volume" of an object.
So, if an object had a mass of 100 grams and a volume of 100 milliliters, the density would be 100 grams / 100 ml.
In the question, water on the surface of the scale would add weight, so the mass of the object that you're weighing would appear to be heavier than it really is. If that happens, you'll incorrectly assume that the density is GREATER than it really is
As an example, suppose that there was 5 ml of water on the surface of the scale. Water has a density of 1 gram per milliliter (1 g/ml) so the water would add 5 grams to the object's weight. If we use the example above, the mass of the object would seem to be 105 grams, rather than 100 grams. So, you would calculate:
density = mass / volume
density = 105 grams / 100 ml
density = 1.05 g/ml
The effect on density would be that it would erroneously appear to be greater
Hope this helps!
Good luck
Answer:
The amount of energy transferred to the diamond while being cut is thus Q = 852000 J
Explanation:
Since quantity of heat transferred Q = mcΔθ where m = mass of substance , c = specific heat capacity of substance and Δθ = temperature change.
Now, given that for diamond, m = mass of diamond = 600 g, c = specific heat capacity of diamond = 710 J/g°C and Δθ = temperature change = 2 °C.
So, the amount of energy transferred to the diamond while being cut is thus
Q = mcΔθ
Q = 600 g × 710 J/g°C × 2 °C
Q = 852000 J
So, the amount of energy transferred to the diamond while being cut is thus Q = 852000 J
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Answers:</u></h2>
<u>1.) Lithium and Sulfide: </u>
- Formula:
- Ion Charges:
<h3 />
<u>2.) Lithium and Chlorine:</u>
- Formula:
- Ion Charges:
<h3 />
<u>3.) Lithium and Oxygen: </u>
- Formula:
- Ion Charges:
<u>4.) Lithium and Nitrogen:</u>
- Formula:
- Ion Charges:
<u>5.) Magnesium and Sulfur:</u>
- Formula:
- Ion Charges:
<u>6.) Magnesium and Chlorine:</u>
- Formula:
- Ion Charges:
<u>7.) Magnesium and Oxygen:</u>
- Formula:
- Ion Charges:
<u>8.) Magnesium and Nitrogen: </u>
- Formula:
- Ion Charges:
<h2 /><h2><u>
Explanation:</u></h2>
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<h3><u>Lithium and Sulfur: </u></h3>
- In order to make Lithium Sulfide, There must be 2 Lithium and 1 Sulfur. You transfer the electrons from both Lithium's to the Sulfur.
<h3 /><h3><u>Lithium and Chlorine:</u></h3>
- In order to make Lithium Chloride, There must be 2 Lithium and 2 Chlorine. You transfer the electrons from both Lithium's to the Chlorines, (One electron for each chlorine.)
<h3 /><h3><u>Lithium and Oxygen:</u></h3>
- In order to make Lithium Oxide, There must be 2 Lithium and 1 Oxygen. You transfer the electrons from both Lithium to Oxygen.
<h3 /><h3><u>Lithium and Nitrogen:</u></h3>
- In order to make Lithium Nitride, There must be 3 Lithium and 1 Nitrogen. You transfer the electrons from all 3 Lithium to Nitrogen.
<h3 /><h3><u>Magnesium and Sulfur:</u></h3>
- In order to make Magnesium Sulfide, There must be 1 Magnesium and 1 Sulfur. You transfer the both electrons from Magnesium to Sulfur.
<h3 /><h3><u>Magnesium and Chlorine:</u></h3>
- In order to make Magnesium Chloride, There must be 1 Magnesium and 2 Chlorine. You transfer on electron to each Chlorine.
<h3 /><h3><u>Magnesium and Oxygen:</u></h3>
- In order to make Magnesium Oxide, There must be 1 Magnesium and 1 Oxygen. You transfer both electrons from Magnesium to Oxygen.
<h3 /><h3><u>Magnesium and Nitrogen:</u></h3>
- In order to make Magnesium Nitride, There must be 3 Magnesium and 2 Nitrogen. You transfer 3 electrons from Magnesium to Nitrogen.
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Given question is incomplete. The complete question is as follows.
The successive ionization energies of a certain third-period element are I1 = 577.9KJ/mol, I2 + 1820 KJ/mol, I3 = 2750 KJ/mol, I4 = 11600 KJ/mol, I5 = 14800 KJ/mol. what element do these ionization energies suggest? Explain your reasoning.
Explanation:
Ionization energy is defined as the energy required to remove the most loosely bound electron from a neutral gaseous atom.
Here, given ionization energies belong to an element present in third period.
We know that second ionization energy will always be greater than third ionization energy.
For the given ionization energies, there is a huge difference between third and fourth ionization energy. This means that there are three valence electrons present in the element.
This is because after losing three electrons it is difficult for the given element to lose fourth electron. Hence, is high as compared to .
Hence, this element has 3 valence electrons and it belongs to 3A group of the periodic table.
Thus, we can conclude that the given unknown element is aluminium (Al).
Answer:
Explanation:
Data provided:
Charge on the glass rod, Q = 0.680 μC = 0.680 × 10⁻⁶ C
Charge on the silk cloth, q = 0.590 μC = - 0.590 × 10⁻⁶ C
Distance between glass rod and the silk cloth, r = 11.0 cm = 0.11 m
now,
The force between (F) the charges is given as:
where,
k is the Coulomb's constant = 9 × 10⁹ N.m²/C²
on substituting the respective values, we get
or