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Sliva [168]
3 years ago
11

Which energy profile best shows that the enthalpy of formation of cs2 is 89.4 kj/mol?

Chemistry
1 answer:
Kruka [31]3 years ago
5 0
Answer is: B. C(s) + 2S(s) + 89.4 kJ → CS2(l).

Missing question:
A. C(s) + 2S(s) → CS2(l) + 89.4 kJ.
B. C(s) + 2S(s) + 89.4 kJ → CS2(l).
C. C(s) + 2S(s) + 89.4 kJ → CS2(l) + 89.4 kJ.
D. C(s) + 2S(s) → CS2(l).
Because enthalpy of the system is greater that zero, this is endothermic reaction (<span>chemical reaction that absorbs more energy than it releases)</span>, heat is included as a reactant.
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agasfer [191]

Answer:

Twice  as much.

Explanation:

That's because the freezing point depression depends on the total number of solute particles.

C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)

0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.

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1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).

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6 0
4 years ago
Which to which! Ahhhh.
jarptica [38.1K]

Answer:

1.a

2. b

Explanation:

Distillation is a process whereby a mixture of liquids having different vapor pressures is separated into its components. At first one might think that this would be quite simple: if you have a solution consisting of liquid A that boils at 50°C and liquid B with a boiling point of 90°C, all that would be necessary would be to heat the mixture to some temperature between these two values; this would boil off all the A (whose vapor could then be condensed back into pure liquid A), leaving pure liquid B in the pot. But that overlooks that fact that these liquids will have substantial vapor pressures at all temperatures, not only at their boiling points.

source: https://chem.libretexts.org/Bookshelves/General_Chemistry/Book%3A_Chem1_(Lower)/08%3A_Solutions/8.09%3A_Distillation

3 0
1 year ago
What is the pressure in atmospheres exerted by a 0.500 mole sample of nitrogen gas in a 10.0 L
Nonamiya [84]

Answer:

The pressure is 1, 22 atm.

Explanation:

We use deal gas formula. First, we convert the unit of temperature in Celsius into Kelvin. We use the constant R= 0,082 l atm /K mol.Then, we solve P (pressure).

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PV=nRT   -----> P= (nRT)/V

P= (0,5 mol x 0,082 l atm /K mol x 298 K)/ 10 L

<em>P= 1, 2218 atm</em>

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