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Sliva [168]
3 years ago
11

Which energy profile best shows that the enthalpy of formation of cs2 is 89.4 kj/mol?

Chemistry
1 answer:
Kruka [31]3 years ago
5 0
Answer is: B. C(s) + 2S(s) + 89.4 kJ → CS2(l).

Missing question:
A. C(s) + 2S(s) → CS2(l) + 89.4 kJ.
B. C(s) + 2S(s) + 89.4 kJ → CS2(l).
C. C(s) + 2S(s) + 89.4 kJ → CS2(l) + 89.4 kJ.
D. C(s) + 2S(s) → CS2(l).
Because enthalpy of the system is greater that zero, this is endothermic reaction (<span>chemical reaction that absorbs more energy than it releases)</span>, heat is included as a reactant.
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D. Metals

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3 years ago
Slicing an average loaf of bread gives 13 medium thickness slices. Each slice of bread is to be coated with 0.0500 oz of mayonna
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Answer:

36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

Explanation:

Number of slices of ham = 231

Given that each sandwich has 1 slice of ham.

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1\times 231 =231 sandwiches

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231\times 2=462

Each bread slice is applied with 0.0500 ounce of mayonnaise.

Then 462 bread slices will have :

462\times 0.0500 ounces=18.48 Oz

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36 loaves of bread and 18.48 ounces of mayonnaise are needed to make all of the sandwiches.

8 0
4 years ago
A method used by the U.S. Environmental Protection Agency (EPA) for determining the concentration of ozone in air is to pass the
baherus [9]

Answer: 1. 9.08\times 10^{-6} moles

2. 90 mg

Explanation:

O_3(g)+2NaI(aq)+H_2O(l) \rightarrow O_2(g)+I_2(s)+2NaOH(aq)

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

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2. \text{Number of moles of ozone}=\frac{0.01331g}{48g/mol}=0.0003moles

According to stoichiometry:

1 mole of ozone is removed by 2 moles of sodium iodide.

Thus 0.0003 moles of ozone is removed by =\frac{2}{1}\times 0.0003=0.0006 moles of sodium iodide.

Mass of sodium iodide= moles\times {\text {molar mass}}=0.0006\times 150g/mol=0.09g=90mg    (1g=1000mg)

Thus 90 mg of sodium iodide are needed to remove 13.31 mg of O_3.

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3 years ago
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