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Slav-nsk [51]
3 years ago
5

(+6) + (+9) (+5) + (+4)

Mathematics
1 answer:
sammy [17]3 years ago
7 0

Answer:

1st:15

2nd:9

Step-by-step explanation:

6+9=15

5+4=9

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I own a large truck, and my neighbor owns four small trucks that are all identical. My truck can carry a load of at least $600$
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Answer:

  there is no greatest load

Step-by-step explanation:

Let x and y represent the load capacities of my truck and my neighbor's truck, respectively. We are given two relations:

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Combining these two inequalities, we have ...

  4/3y ≥ x ≥ y +600

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My truck's capacity is greater than 1800 +600 = 2400 pounds. This is a lower limit. The question asks for an <em>upper limit</em>. The given conditions do not place any upper limit on truck capacity.

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3 years ago
In order to solve the equation below, you need to change it around so that n is by itself. Write this new equation. Do not inclu
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N/6=30
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3 years ago
13 is 6 1/2% of what number?
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200

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1 year ago
We did not find results for: A measure of​ malnutrition, called the​ pelidisi, varies directly as the cube root of a​ person's w
asambeis [7]
\bf \qquad \qquad \textit{double proportional variation}\\\\&#10;\begin{array}{llll}&#10;\textit{\underline{y} varies directly with \underline{x}}\\&#10;\textit{and inversely with \underline{z}}&#10;\end{array}\implies y=\cfrac{kx}{z}\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\

\bf \begin{cases}&#10;p=pedalisi\\&#10;w=weight\\&#10;s=\textit{sitting height}&#10;\end{cases}\quad &#10;\begin{array}{llll}&#10;%pelidisi, varies directly as the cube root of a​ person's weight in grams and inversely as the​ person's sitting height in centimeters.&#10;\textit{pelidisi varies directly}\\&#10;\textit{as cube root of weight}\\&#10;\textit{and inversely to }\\&#10;\textit{sitting height}&#10;\end{array}\implies p=\cfrac{k\sqrt[3]{w}}{s}\\\\&#10;-------------------------------

\bf \textit{we know that }&#10;\begin{cases}&#10;w=48,820\\&#10;s=78.7\\&#10;p=100&#10;\end{cases}\implies 100=\cfrac{k\sqrt[3]{48820}}{78.7}&#10;\\\\\\&#10;100\cdot 78.7=k\sqrt[3]{48820}\implies \cfrac{7870}{\sqrt[3]{48820}}=k&#10;\\\\\\&#10;thus\qquad \boxed{p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{w}}{s}}&#10;\\\\\\&#10;\textit{now, what is \underline{p} when }&#10;\begin{cases}&#10;w=54,688\\&#10;s=72.6&#10;\end{cases}?\implies p=\cfrac{\frac{7870}{\sqrt[3]{48820}}\sqrt[3]{54688}}{72.6}

now, if that value is less than 100, then the fellow is "undernourished", otherwise, is overfed.
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4 years ago
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