Who can help me number 5 please?
2 answers:
You have the right answer I think!!
You have established that c = -2 in question 4.
From the graph, the point g(3)=0 seems usable, so let's go with that.
g(3) = a·b³ - 2 = 0, so a = 2/b³
g(2) = -1 seems also plotted, so g(2) = a·b² - 2 = -1 ⇒ a = 1/b²
Solve for b gives:
2/b³ = 1/b² ⇒ (multiply by b³) 2 = b
From this you can find a=1/4
Note that this is only true if indeed g(3)=0 and g(2)=-1. I just assume that from the graph.
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