Answer:
the least integer for n is 2
Step-by-step explanation:
We are given;
f(x) = ln(1+x)
centered at x=0
Pn(0.2)
Error < 0.01
We will use the format;
[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01
So;
f(x) = ln(1+x)
First derivative: f'(x) = 1/(x + 1) < 0! = 1
2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1
3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2
4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6
This follows that;
Max|f^(n+1) (c)| < n!
Thus, error is;
(n!/(n + 1)!) × 0.2^(n + 1) < 0.01
This gives;
(1/(n + 1)) × 0.2^(n + 1) < 0.01
Let's try n = 1
(1/(1 + 1)) × 0.2^(1 + 1) = 0.02
This is greater than 0.01 and so it will not work.
Let's try n = 2
(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267
This is less than 0.01.
So,the least integer for n is 2
The one that isn’t rationals is B.
The answer would be J because if the equation was transferred into a positive then it would be 2y and 5x marking 5x on the bottom and 2y vertically.
Hope this helps!!
Answer:
Step-by-step explanation:
Area = 1/2 b h
= 1/2 * 4 * 5
= 10 unit^2.
Answer:
71°
Step-by-step explanation:
3x° + (x - 11)° + (2x - 55)° = 360°
3x + x - 11 + 2x - 55 = 360°
6x - 66 = 360°
6x = 360° + 66°
6x = 426°
x = 71°
