Answer:
b) O2, because it has weaker intermolecular forces
Explanation:
The preassure is produced by the collisions of the gas molecules with the walls of its container.
When the intermolecular forces between the gas molecules increase, those molecules start to "slow down" by effect of the interactions. The collisions decrease in frequency and intensity producing a smaller preassure in the container.
Both O2 and Cl2 are non-polar gases and the only intermolecular forces they have are the London ones. Given that the O2 molecules are smaller than the Cl2, the last ones attract each other with more strengh.
Being all that said, the container with the oxygen is expected to have a higher preassure.
Answer:
True
Explanation:
Significant digits include non-zero digits (unless the zero is between two non-zero numbers)
In 12,785.000, there are 5 non-zero digits:
1 2 7 8 5
The new concentration of sodium phosphate is 0.315 mol·L⁻¹.
We can use the dilution formula
:
<em>c</em>₁<em>V</em>₁ = <em>c</em>₂<em>V</em>₂
We can rearrange the formula to get
<em>c</em>₂= <em>c</em>₁ × (<em>V</em>₁/<em>V</em>₂)
∴ <em>c</em>₂ = 1.50 mol·L⁻¹ × (21.00 mL)/(100.0 mL)] = 1.50 mol·L⁻¹ × 0.2100
= 0.315 mol·L⁻¹
The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condensation of ammonia is - 23.3 kJ/mol.
The molar heat of condensation is the opposite of the molar heat of vaporization. The molar heat of vaporization of ammonia is given :
ΔH evaporation = - ΔH condensation
Therefore the molar heat of condensation of ammonia is given by:
ΔH condensation = - 23.3 kJ / mol
That's right. The molar heat of vaporization of ammonia is 23.3 kJ/mol. The molar heat of condesation of ammonia is - 23.3 kJ/mol.
Learn more about heat of condensation at
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