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ruslelena [56]
3 years ago
14

Pls help 25 points, thank you

Chemistry
1 answer:
denis23 [38]3 years ago
7 0

Answer:

how to help people that helps

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A reaction is in equilibrium as shown: A + B C + D. Calculate the equilibrium constant in the final concentrations stabilized at
Butoxors [25]

Answer:

K = 0.167

Explanation:

The equilibrium constant, K of a reaction, is defined as the ratio of the concentrations of products and concentrations of reactants.

For the reactions:

A + B ⇄ C + D

For the definition, K is:

K = [C] [D] / [A] [B]

K = [4.0M] [4.0M] / [9.6M] [10.0M]

<h3>K = 0.167</h3>

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3 years ago
Which of the following is true concerning gamma radiation?
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The answer should be D
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Write the following numbers in scientific notation: a) 0.0006730 b)50000.0 c)0.000003010 d) 132.40 e)2232​
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a)6.730×10⁻⁴

b)5×10⁴

c)3.010×10⁻⁶

d)1.3240×10²

e)2.232×10³

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What is the pOH of a substance with a pH of 10?<br><br>a. 8<br>b. 10<br>c. 14<br>d. 4​
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what is the pOH of a with a pH of 10 14

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An aluminum cup of 140 cm3 capacity is completely filled with glycerin at 20°C. How much glycerin will spill out of the cup if t
mel-nik [20]

Explanation:

The given data is as follows.

    coefficient of volume expansion of glycerin (\beta) = 5.1 \times 10^{-4} 1/^{o}C

     linear expansion coefficient of aluminum, (\alpha_{A}) = 23 \times 10^{-6} 1/^{o}C  

              Volume = 100 cm^{3}

The increase in volume of the cup will be calculated as follows.

                    \Delta V_{c} = V \times 3 \times \alpha \times \Delta T

                                 = 100 cm^{3} \times 3 \times 23 \times 10^{-6} \times (31 - 20)^{o}C

                                 = 75900 \times 10^{-6} cm^{3}

                                 = 0.0759 cm^{3}

Formula for increase in volume  of glycerine is as follows.

               \Delta V_{g} = V \times \beta_{g} \times \Delta T

                              = 100 cm^{3} \times 5.1 \times 10^{-4} 1/^{o}C \times (31 - 20)^{o}C

                              = 0.5610 cm^{3}

Therefore, volume of glycerin spilled is calculated as follows.

                        \Delta V = \Delta V_{g} - \Delta V_{c}

                                     = (0.5610 - 0.0759) cm^{3}

                                     = 0.4851 cm^{3}

Thus, we can conclude that 0.4851 cm^{3} glycerin will spill out of the cup.

6 0
3 years ago
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