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2 years ago

Factor the expression using the GCF. The expression 21m−49n factored using the GCF is...

Mathematics

2 answers:

Roman55 [17]2 years ago

6 0

Answer: 7(3m - 7n)

Step-by-step explanation:

Factor each term then see what value(s) they have in common:

21m - 49n

∧ ∧

3 · 7 · m 7 · 7 · n

Both terms have a 7 in common. What is left over after removing the 7?

21m: 7(3m)

49n: 7(7n)

GCF: 7 Leftovers: 3m and 7n

Factored form of expression is: 7(3m - 7n)

a_sh-v [17]2 years ago

3 0

As 7 is a factor of both 21 and 49, you can take out 7 from both numbers.

7(3m-7n)

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Given the system of equation 7x-3y = 48 .......Eq 1 2x+ y = 35 ........Eq 2 __________ To solve this system by elimination and m

lesya692 [45]

Answer:

x = 11.75

y = 11.5

Step-by-step explanation:

By Elimination Method:

7x - 3y = 48 ---- (1)

2x + y = 35 ----- (2)

Multiply equation (1) by 2 and equation (2) by 7

14x - 6y = 96

14x + 7y = 245

0 -13y = -149

-13y = -149

y = -149/-13

y = 11.5

From equation (2); replace y with 12

2x + y = 35

2x + 11.5 = 35

2x = 35 - 11.5

2x = 23.5

x = 11.75

7 0

2 years ago

A rectangle has a height of k2 + 3 and a width of k2 + 7.

ElenaW [278]

Answer:

The area of the rectangle in polynomial form is $k^4 +10 k^2 + 21$

Step-by-step explanation:

Given

Shape: Rectangle

$Height: k^2 + 3$

$Width: k^2 + 7$

Required

Area of the rectangle

The area of a rectangle is calculated as thus;

$Area = Length * Width$

By substituting $k^2 + 3$ for height and $k^2 + 7$ for width; This gives

$Area = (k^2 + 3)(k^2 + 7)$

Expand the bracket

$Area = k^2(k^2 + 7) + 3(k^2 + 7)$

Open each bracket

$Area = k^2*k^2 + k^2*7 + 3*k^2 + 3*7$

$Area = k^4 +7 k^2 + 3k^2 + 21$

$Area = k^4 +10 k^2 + 21$

Hence, the area of the rectangle in polynomial form is $k^4 +10 k^2 + 21$

5 0

2 years ago

Find the supplement of 0 degrees

jenyasd209 [6]

Answer: The measure of the supplement of an angle of measure 0° is 180°

3 0

1 year ago

Read 2 more answers

Use the quadratic formula to solve for x. 4x2 +9x-1=0

insens350 [35]

Answer:

$x=\frac{-9\pm\sqrt{65} }{8}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define

4x² + 9x - 1 = 0

Step 2: Define variables

a = 4

b = 9

c = -1

Step 3: Find roots

Substitute: $x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}$
Exponents: $x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}$
Multiply: $x=\frac{-9\pm\sqrt{81-16} }{8}$
Subtract: $x=\frac{-9\pm\sqrt{65} }{8}$

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2 years ago

A menu has five choices of appetizers

Vinil7 [7]

The number of the meals possible is 350.

The complete question is given below:-

A menu has 5 choices of appetizers, ten main courses, and seven desserts. How many meals are possible?

<h3 /><h3>What is the combination?</h3>

The arrangement of the different things or numbers in a number of ways is called the combination.

Given that:-

A menu has 5 choices of appetizers, ten main courses, and seven desserts.

The number of the combination of the meals will be calculated as:-

N = 5 x 10 x 7

N = 350

Therefore the number of the meals possible is 350.

To know more about combinations follow

brainly.com/question/11732255

#SPJ1

3 0

1 year ago