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3 years ago

Please answer correctly, will mark brainliest

Mathematics

1 answer:

wel3 years ago

6 0

Answer:

Since the values vary from 0.5 to 4.5, let's take 5 intervals of width 1 unit each

(Lower boundary is included, upper boundary is not)

Average

no. of --------> frequency

movies

_______ __________

0 - 1 --------------> 1

1 - 2 --------------> 5

2 - 3 --------------> 5

3 - 4 --------------> 2

4 - 5 --------------> 1

For frequencies, just count the data values in each interval

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3 years ago

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Igoryamba

Answer:

$\boxed{\sf \ \ \ (fog)(1)=23 \ \ \ }$

Step-by-step explanation:

Hello,

$f(x)=-4x+7\\\\g(x)=2x-6\\\\(fog)(1)=f(g(1)) \ \ \ or \ \ \ g(1)=2-6=-4 \ \ \ so\\(fog)(1)=f(g(1))=f(-4)=-4*-4+7=16+7=23$

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