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Mrrafil [7]
4 years ago
5

Please help!! I don't know how to set this up!!

Mathematics
1 answer:
agasfer [191]4 years ago
6 0

I can't help notice the upper-right-corner picture of "no calculators allowed".


the rate for the prior 50 years has been that,


1950 1/3 of americans were blue-eyed.


2000 1/6 of americans were blue-eyed


so in 50 years, it went from 1/3 to 1/6, well, low and behold, 1/6 is half of 1/3


\bf \cfrac{\quad \frac{1}{3}\quad }{2}\implies \cfrac{\quad \frac{1}{3}\quad }{\frac{2}{1}}\implies \cfrac{1}{3}\cdot \cfrac{1}{2}\implies \cfrac{1}{6}


so, in 2050, namely in 50 years from 2000, we can expect that it'll drop to another half then,


\bf \cfrac{\quad \frac{1}{6}\quad }{2}\implies \cfrac{\quad \frac{1}{6}\quad }{\frac{2}{1}}\implies \cfrac{1}{6}\cdot \cfrac{1}{2}\implies \cfrac{1}{12}

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Check all that apply. If csc =13/5 , then:
nirvana33 [79]

Answer:

The answer are the options B and C

sin(x)=\frac{5}{13}

tan(x)=\frac{5}{12}

Step-by-step explanation:

we know that

csc(x)=\frac{1}{sin(x)}

In this problem we have

csc(x)=\frac{13}{5}

substitute

\frac{13}{5}=\frac{1}{sin(x)}

solve for sin(x)

sin(x)=\frac{5}{13}

cos^{2}(x)+sin^{2}(x)=1

substitute the value of sin(x) and solve for cos(x)

cos^{2}(x)+(\frac{5}{13})^{2}=1

cos^{2}(x)=1-(\frac{5}{13})^{2}

cos^{2}(x)=(\frac{13^{2}-5^{2}}{13^{2}})

cos^{2}(x)=(\frac{144}{13^{2}})

cos^{2}(x)=(\frac{12^{2}}{13^{2}})

cos(x)=(\frac{12}{13})

The function tangent is equal to

tan(x)=\frac{sin(x)}{cos(x)}

substitute the values

tan(x)=\frac{(5/13)}{(12/13)}=5/12

8 0
4 years ago
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Step-by-step explanation:

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Step-by-step explanation:

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0

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Hello,

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