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sveta [45]
4 years ago
14

15 more than twice a number

Mathematics
2 answers:
VikaD [51]4 years ago
8 0

Answer:

15 more than twice a number if it is a certain number u would multiply 15 times what ever number u chose

Step-by-step explanation:

coldgirl [10]4 years ago
3 0

Answer:

15×2x

Step-by-step explanation:

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Read 2 more answers
Suppose that f(5) = 3, f '(5) = 6, g(5) = −5, and g'(5) = 2. Find the following values. (a) (fg)'(5) (b) f g '(5) (c) g f '(5)
baherus [9]

Answer: a) -24

              b) -\frac{36}{25}

              c) 4

Step-by-step explanation:

a) To determine the value of (fg)', use the product rule of derivative, i.e.:

(fg)'(x) = f'(x)g(x) + f(x)g'(x)

(fg)'(5) = f'(5)g(5) + f(5)g'(5)

(fg)'(5) = 6(-5) + 3(2)

(fg)'(5) = -24

b) The value is given by the use of the quotient rule of derivative:

(\frac{f}{g})'(x)=\frac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}

(\frac{f}{g})' (5)=\frac{f'(5)g(5)-f(5)g'(5)}{[g(5)]^2}

(\frac{f}{g})'(5)=\frac{6(-5)-3(2)}{(-5)^{2}}

(\frac{f}{g})'(5)=\frac{-36}{25}

c) (\frac{g}{f})'(5)=\frac{g'(5)f(5)-g(5)f'(5)}{[f(5)]^{2}}

(\frac{g}{f})'(5)=\frac{2(3)-(-5)(6)}{3^{2}}

(\frac{g}{f})'(5)=\frac{36}{9}

(\frac{g}{f})'(5)=4

7 0
3 years ago
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