All categories

2 years ago

What is the area of a rectangle with a length of 3in and a with of 5 square root of 2

Mathematics

1 answer:

abruzzese [7]2 years ago

7 0

Answer:

The area of the rectangle = 15√2 in²

Step-by-step explanation:

What is the area of a rectangle with a length of 3in

and a width of 5√2.

……………………………………………

FORMULA :

area of a rectangle = length × width

===============================

Then

The area of the rectangle = 3 × 5√2 = 15√2

You might be interested in

Rewrite the expressions using radical notation

Ber [7]

Tip:

You put the number of each equation into the form.

Exponent’s denominator goes outside

Exponent’s numerator goes inside with the number

4 0

2 years ago

I’m unsure how to solve this... help?

dem82 [27]

Time taken is equal to distance divided by speed
So time is 50/5 = 10 seconds

5 0

3 years ago

Read 2 more answers

A certain radioactive isotope has a half-life of 15 days. If one is to make a table showing the half-life decay of a sample of t

Verdich [7]

A half-life of the isotope is 15 days and at start its mass is 32 g.
A table:
t: m:
0 32 g
15 16 g
30 8 g
45 4 g
60 2 g
75 1 g
In the first column is used an arithmetic sequence ( a 1 = 0, d = 15 ).
In the second column is used a geometric sequence ( a 1 = 32, r = 1/2 )

7 0

3 years ago

What is the value of x?<br><br> Enter your answer in the box. <br><br> x = ___

lapo4ka [179]

Answer:

x=8

Explanation:

The picture tells us that the triangle is equilateral (this means that each angle is 60°). We can assume this because each side has been marked with the same line.

Because each angle is equal to 60°, this means that:

7x+4=60

Now solve for x:

7x=56
x=8

5 0

3 years ago

A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent

kotykmax [81]

Answer:

Comparing the p value with the significance level $\alpha=0.01$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.

Step-by-step explanation:

$\bar X_{1}=15$ represent the mean for sample 1

$\bar X_{2}=18$ represent the mean for sample 2

$s_{1}=5$ represent the sample standard deviation for 1

$s_{f}=6$ represent the sample standard deviation for 2

$n_{1}=49$ sample size for the group 2

$n_{2}=64$ sample size for the group 2

$\alpha=0.01$ Significance level provided

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}\neq 0$

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

And the degrees of freedom are given by $df=n_1 +n_2 -2=49+64-2=111$

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:

$t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897$

P value

Since is a bilateral test the p value would be:

$p_v =2*P(t_{111}$

7 0

3 years ago