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ASHA 777 [7]
3 years ago
9

What is this method called?????​

Mathematics
1 answer:
Serga [27]3 years ago
8 0

Answer:

The algebraic method is a collection of several methods used to solve a pair of linear equations with two variables.

Step-by-step explanation:

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It's the last answer. Think about when you move a point on a graph left 4 spaces it's on the x axis. Because it's going left it's going towards the negative numbers hence minus and not plus. some concept for the y axis.
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Maria has a bag with 6 red marbles , 6 blue marbles , and 4 green marbles . Without looking Maria pick one marble. She does not
podryga [215]
40%

The probability of her getting a red marble is the number of red marbles divided by the number of total marbles. Since she picked a green marble first, we must subtract one marble from the total number of marbles, so that the total # of marbles is 6 + 6 + 4 = 16 - 1 (green marble) = 15. Since there are 6 red marbles, our probability is 6/15 or 2/5. Converted to percentage form, this is 0.4 —> 40%
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How many factors are in the expression p(q-1)^r
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Read 2 more answers
What is the equation for x+1, x+2, x+3
arlik [135]
<span>Hello there.

What is the equation for x+1, x+2, x+3

</span><span>4x</span>+<span>3</span>
4 0
3 years ago
For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0
2 years ago
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