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mr Goodwill [35]
3 years ago
5

What is the density of a piece of wood that has a mass of 35.0 grams and a volume of 26.4 cm3

Chemistry
1 answer:
vladimir2022 [97]3 years ago
3 0

Answer:

We have the final answer as

<h2>1.33 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

<h3>density =  \frac{mass}{volume}</h3>

From the question

mass = 35 g

volume = 26.4 cm³

The density of the wood is

density =  \frac{35}{26.4}  \\ 1.325757575757...

We have the final answer as

<h3>1.33 g/cm³</h3>

Hope this helps you

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c) there are two kinds of mixtures : homogenous and heterogenous

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1 Identify Draw an example of a force acting on an object.
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Answer below

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Many electrophilic aromatic halogenations require the presence of aluminum trihalide (halide-chloride or bromide) as a catalyst.
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4 years ago
A silver block, initially at 57.2 ∘C, is submerged into 100.0 g of water at 24.8 ∘C, in an insulated container. The final temper
Masteriza [31]

Answer:

96.5 grams is the mass of the silver block.

Explanation:

Heat lost by iron will be equal to heat gained by the water

-Q_1=Q_2

Mass of iron = m_1=?

Specific heat capacity of silver= c_1=0.240 J/g^oC

Initial temperature of the silver= T_1=120^oC

Final temperature = T_2=T=26.5^oC

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=100.0 g

Specific heat capacity of water= c_2=4.184 J/g^oC

Initial temperature of the water = T_3=24.8 ^oC

Final temperature of water = T_2=T=26.5^oC

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(m_1\times 0.240 J/g^oC\times (26.5^oC-57.2^oC))=100.0 g\times 4.184 J/g^oC\times (26.5^oC-24.8^oC)

we get, m_1 = 96.5 g

96.5 grams is the mass of the silver block.

5 0
4 years ago
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