The density of He is 1.79 x 10⁻⁴ g/mL
In other words in 1 mL there's 1.79 x 10⁻⁴ g of He.
To fill a volume of 6.3 L the mass of He required
= 1.79 x 10⁻⁴ g/mL * 6300 mL
= 11 277 * 10⁻⁴ g
Therefore mass of He required = 1.1277 g of He

8 0

3 years ago

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Determine the soil texture for the following combinations of sand, silt, and clay.

JulijaS [17]

Answer:

a. Clay

b. Sandy Loam

c. Sandy Clay

d. Loamy Sand

Explanation:

Based on the soil texture triangle, the soil texture for the following combination of sand, silt and clay are;

a. Sand 20 percent; Silt 20 percent;Clay 60 percent: ____ CLAY

b. Sand 60percent; Silt 30percent; Clay 10percent: ___ SANDY LOAM

c. Sand 50percent; Silt 10percent;Clay 40 percent: ____ SANDY CLAY

d. Sand 80 percent; Silt 15 percent; Clay 5percent:_____ LOAMY SAND

7 0

3 years ago

According to the Law of Conservation of Mass, how much water is produced if 22.5 g of

nadezda [96]

Answer: The amount of water produced is 9.3 grams

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$CH_4+2O_2\rightarrow CO_2+2H_2O$

mass of reactants = mass of methane + mass of oxygen = 22.5 g + 35.7 g = 58.2 g

mass of products = mass of carbon dioxide + mass of water = 48.9 g + mass of water

48.9 g + mass of water = 58.2 g

mass of water = 9.3 g

4 0

3 years ago