Ask question

Ask question

All categories

3 years ago

5

What’s the greatest common factors for 24 and12

1 answer:

Olegator [25]3 years ago

4 0

The answer is 12.

12 ⇒ 1 × 12

24 ⇒ 2 × 12

You might be interested in

Which is a prime number<br>a.67<br>b.65<br>c.63<br>d.60

juin [17]

The answer is 67 :)))

4 0

3 years ago

Read 2 more answers

Helppp 1,2,3,4,5 please as fast as you can

Vladimir [108]

Weather I think I'm not sure

6 0

3 years ago

Read 2 more answers

Solve. Answer with a number only. -2/5(x+6)=10

malfutka [58]

Answer:

x= -31

Step-by-step explanation:

3 0

3 years ago

You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

3 years ago

2x + 9x2 + 4x + 4xy – 6x2

Harlamova29_29 [7]

Simplified would be 4xy + 3x^2 + 6x

7 0

3 years ago

Read 2 more answers