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aksik [14]
3 years ago
14

What are the solutions to the equation (x – 2)(x + 5) = 0?

Mathematics
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

(2,-5)

Step-by-step explanation:

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A trapezoid has a set of parallel bases with lengths 3 inches and 5 inches and a helght of 8 inches. What is the area
Aleks04 [339]

Answer:

The area of trapezoid is 32 inches^2

Step-by-step explanation:

Parallel base 1 = a = 3 inches

Parallel base 2 = b = 5 inches

Height of trapezoid = 8 inches

We need to find area of trapezoid

The formula used is: Area\:of\:trapezoid=\frac{a+b}{2}\times h

Now putting the values and finding area of trapezoid

Area\:of\:trapezoid=\frac{a+b}{2}\times h\\Area\:of\:trapezoid=\frac{5+3}{2}\times 8\\Area\:of\:trapezoid=\frac{8}{2}\times 8\\Area\:of\:trapezoid=4\times 8\\Area\:of\:trapezoid=32

So, the area of trapezoid is 32 inches^2

7 0
3 years ago
Maximize and minimize quantities given an expression with two variables Question Find the difference between the maximum and min
Zolol [24]

Answer:

The difference between the maximum and minimum is

\left(\displaystyle\frac{5}{63}\right)^2\left(\displaystyle\frac{625}{63}\right)^{250}

Step-by-step explanation:

Since p = 10-q, we can replace p in the expression and we get a single-variable function

f(q)=(10-q)^2q^{250}

Taking the derivative with respect to q and using the rule for the derivative of a product

f'(q)=-2(10-q)q^{250}+250(10-q)^2q^{249}

Critical point (where f'(q)=0)

Assuming q≠ 0 and  q≠ 10

f'(q)=0\Rightarrow -2(10-q)q^{250}+250(10-q)^2q^{249}=0\Rightarrow\\\\\Rightarrow 250(10-q)=2q\Rightarrow q=\displaystyle\frac{625}{63}

To check this is maximum, we take the second derivative

f''(q)=63252q^{250}-1255000q^{249}+6225000q^{248}

and  

f''(625/63) < 0

so q=625/63 is a maximum. For this value of q we get p=5/63

The maximum value of

p^2q^{250}

is

\left(\displaystyle\frac{5}{63}\right)^2\left(\displaystyle\frac{625}{63}\right)^{250}

The minimum is 0, which is obtained when q=0 and p=10 or q=10 and p=0

The difference between the maximum and minimum is then

\left(\displaystyle\frac{5}{63}\right)^2\left(\displaystyle\frac{625}{63}\right)^{250}

3 0
3 years ago
Math question, any help is appreciated :)
natka813 [3]

Answer:

B and D

Step-by-step explanation:

A simplifies to a linear equation

C is a cubic

The other 2 are quadratic and can be solve using the formula

8 0
3 years ago
What is the solution to 5(34+12)/2?
Firlakuza [10]
The answer is 115. ;) 
7 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
MAVERICK [17]
The answer is 18.2% I believe.

3 0
3 years ago
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