Answer:
Step-by-step explanation:
the curve is representing the projectile. at t=0, the projectile is on the ground. at t=6, the projectile has finished its journey and is back on the ground. In between t=0 and t=6 will be the projectile's peak altitude. the point between t=0 and t=6 is t=3. So plug in t=3 and solve for s(t), and you get 36ft. gg
8x + 6y = 10 ----------- (1)
5x - 3y = 2.2 ---------- (2)
(2) x 2:
10 x - 6y = 4.4 --------(2a)
(2a) + (1)
18x = 14.4
x = 1.8 ------- sub into (1)
8 (1.8) + 6y = 10
14.4 + 6y = 10
6y = 10 - 14.4
6y = - 4.4
y = - 0.73
There is 1 set of solution to it. (Answer C)
<span>-15r + 3(2s - 4r)
=</span><span>-15r + 6s - 12r
= -27r + 6s
or
= 6s - 27r</span>
Answer:
The weight of the parcel is approximately 6 kilograms.
Step-by-step explanation:
The weight of the parcel is 12 lbs and 8 oz.
1 lb = 16 oz
So, 8 oz = lb.
That means, 12 lbs and 8 oz = (12 + 0.5) lbs = 12.5 lbs
Now, 1 lb = 454 g
So, 12.5 lbs = (12.5 × 454) g = 5675 g
As, 1 kilogram = 1000 g
That means, 1 g = 0.001 kilogram
So, 5675 g kilograms. (Rounded to the nearest whole kilogram)
Thus, the weight of the parcel is approximately 6 kilograms.
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