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3 years ago

I need help pls ASAP

Mathematics

2 answers:

11111nata11111 [884]3 years ago

8 0

Answer:

Step-by-step explanation:

LV is half of XV so basically 38 divided by 2

HACTEHA [7]3 years ago

6 0

Answer:

Step-by-step explanation:

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Pls help with year 8 maths

agasfer [191]

Answer:

a) 1

b)11

c)4

d)1

I hope it helps you...

3 0

3 years ago

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Elena is buying cups and plates for her party. Cups are sold in packs of 8 and plates are sold in packs of 6. She wants to have

Svet_ta [14]

Answer:

For 80 people, Elena would need

14 packs of plates and 10 packs of cups

She would have at least 80 of each.

I am not completely sure of this, sorry if wrong.

Step-by-step explanation:

80 people

8 cups per pack

6 plates per pack

8, 16, 24, 32, 40, 48, 56, 64, 72, 80

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84

LCM (least common multiple) = 24

8 0

3 years ago

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Please anyone help me on this...

OLga [1]

Answer:

The 2nd choice ( the one that starts with square root of 5 )

Step-by-step explanation:

I turned all of the choices into decimals so they had the same playing field then I put them from least to greatest and I got square root of five, 5/2, 2.717171717171, 2 and 3/4.

7 0

3 years ago

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QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu

Harman [31]

Answer:

(a)Revenue function, $R(x)=580x-x^2$

Marginal Revenue function, R'(x)=580-2x

(b)Fixed cost =900 .

Marginal Cost Function=300+50x

(c)Profit, $P(x)=-35x^2+280x-900$

(d)x=4

Step-by-step explanation:

Part A

Price Function $= 580 - 10x$

The revenue function

$R(x)=x\cdot (580-10x)\\R(x)=580x-x^2$

The marginal revenue function

$\dfrac{dR}{dx}= \dfrac{d}{dx}(R(x))=\dfrac{d}{dx}(580x-x^2)=580-2x\\R'(x)=580-2x$

Part B

(Fixed Cost)

The total cost function of the company is given by $c=(30+5x)^2$

We expand the expression

$(30+5x)^2=(30+5x)(30+5x)=900+300x+25x^2$

Therefore, the fixed cost is 900 .

Marginal Cost Function

If $c=900+300x+25x^2$

Marginal Cost Function, $\frac{dc}{dx}= (900+300x+25x^2)'=300+50x$

Part C

Profit Function

Profit=Revenue -Total cost

$580x-10x^2-(900+300x+25x^2)\\580x-10x^2-900-300x-25x^2\\$Profit,P(x)=-35x^2+280x-900$

Part D

To maximize profit, we find the derivative of the profit function, equate it to zero and solve for x.

$P(x)=-35x^2+280x-900\\P'(x)=-70x+280\\-70x+280=0\\-70x=-280\\$Divide both sides by -70\\x=4$

The number of cakes that maximizes profit is 4.

6 0

3 years ago

Whats the answer??? Pleaseeee!!!!

kvasek [131]

To find the 20th term in this sequence, we can simply keep on adding the common difference all the way until we get up to the 20th term.

The common difference is the number that we are adding or subtracting to reach the next term in the sequence.

Notice that the difference between 15 and 12 is 3.

In other words, 12 + 3 = 15.

That 3 that we are adding is our common difference.

So we know that our first term is 12.

Now we can continue the sequence.

12 ⇒ 1st term

15 ⇒ 2nd term

18 ⇒ 3rd term

21 ⇒ 4th term

24 ⇒ 5th term

27 ⇒ 6th term

30 ⇒ 7th term

33 ⇒ 8th term

36 ⇒ 9th term

39 ⇒ 10th term

42 ⇒ 11th term

45 ⇒ 12th term

48 ⇒ 13th term

51 ⇒ 14th term

54 ⇒ 15th term

57 ⇒ 16th term

60 ⇒ 17th term

63 ⇒ 18th term

66 ⇒ 19th term

69 ⇒ 20th term

This means that the 20th term of this arithemtic sequence is 69.

5 0

4 years ago