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natali 33 [55]
3 years ago
7

A sealed flask contains 1.3 x 10^25 molecules of CO2. How many moles of CO2 are in the flask?

Chemistry
2 answers:
GenaCL600 [577]3 years ago
8 0
A mole of anything contains 6.022x10^23 items. so we need to divide this

1.3 x 10^25 / 6.022 x 10^23 = 21.59 moles
Katarina [22]3 years ago
8 0

Answer : The moles of CO_2 in the flask are, 21.58 moles.

Solution :

As we are given the molecules of CO_2 in the flask are =1.3\times 10^{25}. Now we have to calculate the moles of CO_2 in the flask.

As, 6.022\times 10^{23} molecules of CO_2 present in 1 mole of CO_2.

So, 1.3\times 10^{25} molecules of CO_2 present in \frac{1.3\times 10^{25}}{6.022\times 10^{23}}=21.58 moles of CO_2.

Therefore, the moles of CO_2 in the flask are, 21.58 moles.

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The total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

<h3>Heat evolved in converting the steam to ice</h3>

The total heat evolved is calculated as follows;

Q(tot) = Q1(steam to boiling point) + Q2(boiling point to ice) +Q3(freezing to -42 ⁰C)

where;

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Q = = mcΔθ

where;

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  • c is specific heat capacity,
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Q(tot) = 2(18)(2.01)(100 - 135) + 2(18)(2.01)(0 - 100) + 2(18)(2.09)(-42 - 0)

Q(tot) = -12,928.68 J

Thus, the total quantity of heat evolved in converting the steam to ice is determined as  -12,928.68 J.

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8 0
2 years ago
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<u>Answer:</u>

All of the limiting reagent gets used up causes the percent yield of a reaction to be less than 100%

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The limiting reactant can be found easily by calculating the yield of each reactant assuming they are consumed completely. The reactant which has least yield is the limiting reactant of the reaction.

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