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atroni [7]
3 years ago
11

Identify the correct mole ratio for each substance. Sodium chloride (NaCl) Na:Cl = 1: Ammonium nitrate (NHNO) H:O = 4:

Chemistry
2 answers:
Norma-Jean [14]3 years ago
4 0

<u>Answer:</u> The mole ratio of H : O in ammonium nitrate is 4 : 3.

<u>Explanation:</u>

We are given a compound named ammonium nitrate having formula NH_4NO_3

There are 3 elements in this compound which are nitrogen, hydrogen and oxygen.

To calculate the mole ratio, we write the ratio of their subscripts. For this compound, it is:

N:H:O::2:4:3

The mole ratio of H and O for this compound is 4 : 3.

vesna_86 [32]3 years ago
3 0

Correct answers are Sodium chloride (NaCl) Na:Cl = 1:1 Ammonium nitrate (NHNO) H:O = 4:3

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Calculate the theoretical yield of alum expected from 0.9875 g of aluminum foil. assume the aluminum is the limiting reactant.
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Answer: 17.34 grams of alum will be produced if 0.9875 g of Aluminium foil was used.

Explanation: Reaction to form alum from Aluminium is given as:

2Al(s)+2KOH(aq.)+2H_2O(l)+4H_2SO_4(aq.)\rightarrow 2KAl(SO_4)_2(s).12H_2O(l)+3H_2(g)

We are given Aluminium to be the limiting reactant, so the formation of alum will be dependent on Aluminium because it limits the formation of product.

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2 moles of Al is producing 2 moles of Alum

Mass of 2 moles of Aluminium = (2 × 27)g/mol = 54 g/mol

Mass of 2 moles of alum = (2 × 474)g/mol = 948 g/mol

54 g/mol of aluminium will produce 948 g/mol of alum, so

\text{0.9875 grams of aluminium will produce}=\frac{948g/mol}{54g/mol}\times 0.9875g

Amount of Alum produced = 17.34 grams

Theoretical yield of alum = 17.34 grams.

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