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atroni [7]
2 years ago
11

Identify the correct mole ratio for each substance. Sodium chloride (NaCl) Na:Cl = 1: Ammonium nitrate (NHNO) H:O = 4:

Chemistry
2 answers:
Norma-Jean [14]2 years ago
4 0

<u>Answer:</u> The mole ratio of H : O in ammonium nitrate is 4 : 3.

<u>Explanation:</u>

We are given a compound named ammonium nitrate having formula NH_4NO_3

There are 3 elements in this compound which are nitrogen, hydrogen and oxygen.

To calculate the mole ratio, we write the ratio of their subscripts. For this compound, it is:

N:H:O::2:4:3

The mole ratio of H and O for this compound is 4 : 3.

vesna_86 [32]2 years ago
3 0

Correct answers are Sodium chloride (NaCl) Na:Cl = 1:1 Ammonium nitrate (NHNO) H:O = 4:3

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777dan777 [17]

Answer:

I am not really sure, but I think Fr.

Explanation:

8 0
2 years ago
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What is true about all plutons? They form near Earth’s surface. They form below Earth’s surface. They cut across other rock laye
pishuonlain [190]

<u>Answer:</u> The correct answer is that they are formed below Earth's surface.

<u>Explanation:</u>

Plutons are defined as the intrusive igneous rocks named as plutonic rocks which are formed when the magma gets cools down slowly and solidifies below the Earth's surface.

It is different from volcanic rocks which are formed when lava gets cools down and solidifies on the Earth's surface.

Hence, the correct answer is that they are formed below Earth's surface.

7 0
2 years ago
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An equilibrium mixture of O2, SO2 and SO3 contains equal concentrations of SO2 and SO3.
AleksAgata [21]

Answer:

[O₂(g)] = 0.0037M

Explanation:

            2SO₂(g) + O₂(g) => 2SO₃(g)

Conc:   [SO₂(g)]   [O₂(g)]     [SO₃(g)]  and  [SO₂(g)] = [SO₃(g)]

Kc =  [SO₃(g)]²/[O₂(g)][SO₂(g)]² => Kc = 1/[O₂(g)] = 270 if [SO₂(g)] = [SO₃(g)]

∴ [O₂(g)] = (1/270)M = 0.0037M  

7 0
3 years ago
Silver nitrate reacts with aluminum chloride to form the insoluble compound, silver chloride. The reaction proceeds according to
viva [34]

The theoretical yield of silver chloride, AgCl is 5.2109 g

The balanced equation for the reaction is given below:

<h3>3AgNO₃(aq) + AICI₃(aq) —> Al(NO₃)₃ (aq) + 3AgCl (s) </h3>

Next, we shall determine the mass of aluminum chloride, AICI₃ that reacted and the mass of silver chloride, AgCl produced from the balanced equation. This is illustrated below:

Molar mass of AICI₃ = 133.34 g/mol

Mass of AICI₃ from the balanced equation = 1 × 133.34 = 133.34 g

Molar mass of AgCl = 143.32 g/mol

Mass of AgCl from the balanced equation = 3 × 143.32 = <em>429.96 g</em>

<h3>SUMMARY</h3>

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Finally, we shall determine the theoretical yield of AgCl by the reaction of 1.616 g of AICI₃ as follow:

From the balanced equation above,

133.34 g of AICI₃ reacted to produce 429.96 g of AgCl.

Therefore,

1.616 g of AICI₃ will react to produce = \frac{1.616 * 429.96}{133.34} = 5.2109 g of AgCl.

Thus, the theoretical yield of silver chloride, AgCl is 5.2109 g

Learn more: brainly.com/question/24653699

3 0
3 years ago
The specific heat values of most _____ tend to be quite low
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This answer would be heat capacity
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