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Debora [2.8K]
3 years ago
15

Please please help! I will give brainliest if I can, to whoever answers the best!

Mathematics
1 answer:
____ [38]3 years ago
7 0

Answer: D) y = 0.5x - 3

Step-by-step explanation: y = mx + b, m = slope, b = y intercept

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Identify the population. Determine whether each sample is a random sample or a biased sample.
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3 years ago
Read 2 more answers
Please someone help me get this question correct.
Mazyrski [523]
For the first one it would be:
C(800)=600

The second would be:
C(200)=e

And the third would be:
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4 years ago
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Step-by-step explanation:

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3 years ago
Determine which of the following sets of three points constitute the vertices of a right triangle: (a) 3 + 5i,2 +2i,5i; (b)2i,3
Illusion [34]

Answer:

Option (c) is correct

Step-by-step explanation:

Case (a)

A = 3 + 5i = (3, 5)

B = 2 + 2i = (2, 2)

C = 5i = (0, 5)

Use the distance formula to find the distance between two points

AB = \sqrt{(2-3)^{2}+(2-5)^{2}}=\sqrt{10}

BC = \sqrt{(0-2)^{2}+(5-2)^{2}}=\sqrt{13}

CA = \sqrt{(0-3)^{2}+(5-5)^{2}}=\sqrt{9}

For the triangle to be right angles triangle

BC^{2}=AB^{2}+CA^{2}

Here, it is not valid, so these are not the points of a right angled triangle.

Case (b)

A = 2i = (0, 2)

B = 3 + 5i = (3, 5)

C = 4 + i = (4, 1)

Use the distance formula to find the distance between two points

AB = \sqrt{(3-0)^{2}+(5-2)^{2}}=\sqrt{18}

BC = \sqrt{(4-3)^{2}+(1-5)^{2}}=\sqrt{17}

CA = \sqrt{(4-0)^{2}+(1-2)^{2}}=\sqrt{17}

For the triangle to be right angles triangle

AB^{2}=BC^{2}+CA^{2}

Here, it is not valid, so these are not the points of a right angled triangle.

Case (c)

A = 6 + 4i = (6, 4)

B = 7 + 5i = (7, 5)

C = 8 + 4i = (8, 4)

Use the distance formula to find the distance between two points

AB = \sqrt{(7-6)^{2}+(5-4)^{2}}=\sqrt{2}

BC = \sqrt{(8-7)^{2}+(4-5)^{2}}=\sqrt{2}

CA = \sqrt{(8-6)^{2}+(4-4)^{2}}=\sqrt{4}

For the triangle to be right angles triangle

CA^{2}=BC^{2}+AB^{2}

Here, it is valid, so these are the points of a right angled triangle.

7 0
3 years ago
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