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frozen [14]
3 years ago
7

Alcoholic beverages contain

Chemistry
1 answer:
oksian1 [2.3K]3 years ago
5 0

Answer:

A drink containing ethanol / ethyl alcohol is literally any drink

Explanation:

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8.
devlian [24]
The answer is A because I did this before
8 0
3 years ago
Read 2 more answers
What is the specific heat of a 123 g substance that requires 4.56 J of heat in
vladimir1956 [14]

Answer:  A. 0.00301J/g^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed  = 4.56 J

m = mass of substance = 123 g

c = specific heat capacity = ?

Change in temperature ,\Delta T=T_f-T_i=12.32^0C

Putting in the values, we get:

4.56J=123g\times c\times 12.32^0C

c=0.00301J/g^0C

The specific heat of a 123 g substance that requires 4.56 J of heat in  order to increase its temperature by 12.32 °C is 0.00301J/g^0C

8 0
3 years ago
Find the empirical and molecular formula for a molar mass of 60.10g/mol; 39.97% carbon 13.41% hydrogen: 46.62% nitrogen
PSYCHO15rus [73]
Assuming we have 100g, this means that

39.97g Carbon * 1 mol / 12 g = 3.33 mol Carbon
13.41g Hydrogen * 1 mol/1 g = 13.41 mol Hydrogen
46.62g Nitrogen * 1 mol / 14 g = 3.33 mol Nitrogen
Dividing everything by 3.33, we get

1 mol Carbon, 4.03 mol Hydrogen, 1 mol Nitrogen.

Empirical formula is CH4N

<span>The mass of the empirical formula is
12 + 4 + 14 = 30

Since the molar mass is double, we multiply all our subscripts

The molecular formula is C2H8N2

The answers to this question are </span><span>an empirical formula of CH4N</span> and a molecular formula of C2H8N2 .
5 0
3 years ago
Convert 35 joules into calories.<br> OR 1.410 cal<br> OC 82,500 cal<br> OD. 1.420,000 cal
lesya692 [45]

Answer:

0.83Cal

Explanation:

Given parameters:

   Amount of energy given;

      35J;

 Convert to Cal;

         1 calorie  = 42 joules

         x calories  = 35 joules

   Cross multiply;

         42x = 35

             x = \frac{35}{42}   = 0.83Cal

7 0
3 years ago
When the moon is between the earth and the sun how is the moon most likely seen
kvasek [131]

Its seen like the lunar shadow

7 0
4 years ago
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