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3 years ago

The number of electrons in an ion with 20 protons and an ionic charge of 2- is

Chemistry

1 answer:

Hitman42 [59]3 years ago

7 0

The number electrons in an ion with 20 protons and a 2- charge is 22electrons total hope this helps!

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What is the mass number of a atom that has 4 protons 4electrons 5neutrons

user100 [1]

Answer:

<h3><em>Please make sure to re-write this on your own so your teacher doesn't think that your cheating!</em></h3>

Explanation:

A neutral atom will have the same number of electrons does protons. Since it has 4 protons, it must have an atomic number of 4. (That will make it beryllium.) Since it has 4 protons and 5 neutrons, it has a mass number of 9.

So the answer is 9

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3 years ago

Why are little pieces of cardboard lighter than a whole piece of cardboard?

Ilia_Sergeevich [38]

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3 years ago

Read 2 more answers

What element has 2 electrons in the 4s sub level?

ruslelena [56]

is the Calcium because the calcium in group two which group two has 2 electron and also calcium and Potassium 4s sub level group potassium has 1 electron. :)

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3 years ago

The bond enthalpy in NO is 632 kJ/mol and that of each NO bond in NO2 is 469 kJ/mol. Explain the difference in bond enthalpies b

Ivanshal [37]

Answer:

Explanation:

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3 years ago

WHAT MASS OF 1,1 DICHLOROEHTANE MUST BE MIXED WITH 100G OF 1,1 DICHLOROTETRAFLUOROEHTANE TO GIVE A SOLUTION WITH VAPOR PRESSURE

vaieri [72.5K]

This is an incomplete question.

The complete question is:

1,1-dichlorotetrafluoroethane, CF3CCL2F, has a vapor pressure of 228 torr. What mass of 1,1-dichloroethane must be mixed with 100.0 g of 1,1-dichlorotetrafluoroethane to give a solution with vapor pressure 157 torr at 25 degrees celsius?

Answer: 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at $25^0C$

Explanation:

As the relative lowering of vapor pressure is directly proportional to the amount of dissolved solute.

The formula for relative lowering of vapor pressure will be,

$\frac{p^o-p_s}{p^o}=i\times x_2$

where,

$\frac{p^o-p_s}{p^o}$ = relative lowering in vapor pressure

i = Van'T Hoff factor = 1 (for non electrolytes)

$x_2$ = mole fraction of solute

= $\frac{\text {moles of solute}}{\text {total moles}}$

Given : x g of solute is present in 100 g of solvent

moles of solute (1,1 DICHLOROEHTANE) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{xg}{98.96g/mol}moles$

moles of solvent (1,1 DICHLOROTETRAFLUOROEHTANE ) = $\frac{\text{Given mass}}{\text {Molar mass}}=\frac{100g}{170.92g/mol}=0.58moles$

Total moles = moles of solute + moles of solvent = $\frac{xg}{98.96g/mol}+0.58$

$x_2$ = mole fraction of solute = $\frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$\frac{228-157}{157}=1\times \frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$0.45=1\times \frac{\frac{xg}{98.96g/mol}}{\frac{xg}{98.96g/mol}+0.58}$

$x=46.9g$

Thus 46.9 g of 1,1 dichloroethane must be fixed with 100 g of 1,1 dichlorotetrafluoroethane to give a solution with vapor pressure of 157 torr at $25^0C$

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4 years ago