4<span>(9<span>a2</span>−6a+1<span>)
Answer:</span></span>4<span><span><span>(3a−1)</span>2</span><span>4<span><span>(3a-1)</span>2</span></span></span>
Answer:
Proved
Step-by-step explanation:
To prove that every point in the open interval (0,1) is an interior point of S
This we can prove by contradiction method.
Let, if possible c be a point in the interval which is not an interior point.
Then c has a neighbourhood which contains atleast one point not in (0,1)
Let d be the point which is in neighbourhood of c but not in S(0,1)
Then the points between c and d would be either in (0,1) or not in (0,1)
If out of all points say d1,d2..... we find that dn is a point which is in (0,1) and dn+1 is not in (0,1) however large n is.
Then we find that dn is a boundary point of S
But since S is an open interval there is no boundary point hence we get a contradiction. Our assumption was wrong.
Every point of S=(0, 1) is an interior point of S.
First you have to make the assumption that these are the only two outcomes. There is also the possibility of hitting the ball and getting out.
However, if we assume that these are the only two cases, we know that the probability is 58.3%. This is because it has been on base 7 times out of 12.
9514 1404 393
Answer:
x = 3/2
Step-by-step explanation:
Multiply by 3 and solve the resulting 2-step equation.
5 = (1/3)(2x +12)
15 = 2x +12 . . . . . . multiply by 3
3 = 2x . . . . . . . . . . subtract 12
3/2 = x . . . . . . . . . . divide by 2
Answer:
X=3
Step-by-step explanation:
12+2x=6x
