<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? </h3>
<em>First we have to find the factors of 15x³y²</em>
<em>15x³y² = 3 * 5x³y² </em>
<em>Then we have to find the factors of 20x⁴y⁴</em>
<em>20x⁴y⁴ = 2²x¹y² * 5x³y²</em>
<em>Now we have to find the common factors to both numbers.</em>
<em>The common factors are </em><em>5x³y²</em>
Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²
Hope this helps!
Answer:
C <em>,</em><em> </em><em>negative</em><em> </em><em>two</em><em> </em><em>times</em><em> </em><em>a </em><em>number</em><em>,</em><em> </em><em>plus</em><em> </em><em>seven </em><em>,</em><em> </em><em>is </em><em>fewer</em><em> </em><em>than </em><em>twenty</em><em>-seven </em><em>and </em><em>five </em><em>tenths </em>
Answer:
The speed of the wind is 12 miles per hour.
Step-by-step explanation:
Given that the plane travels 264 miles in 1.1 hours with a headwind, the following calculation must be performed to determine its speed:
264 / 1.1 = X
240 = X
Thus, the speed of the plane into the headwind was 240 miles per hour. Now, on the return, with the wind in favor, the route is completed in exactly 1 hour.
Therefore the wind exerts a difference of 24 miles per hour between one trip and another, with which, if it remains stable, its speed is 12 miles per hour (24 / 2).
Answer:
9x + 1 = 7x + 13
<=> 2x = 12
<=> x = 6
with x = 6, UW = 7.6 + 13 = 55
Step-by-step explanation:
.......
