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pickupchik [31]
3 years ago
12

Using the quadratic formula to solve x2 = 5 – x, what are the values of x?

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
5 0
Hello : 
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a <span>≠ 0) is :
</span><span>Δ = b² -4ac
1 )  </span>Δ > 0  the equation has two reals solutions : x =  (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ <span>< 0 : no reals solutions
in this exercice : x² = 5-x
x² +x-5 = 0    .... a =1   b= 1   c=-5
calculate </span>Δ..................................
barxatty [35]3 years ago
4 0

Answer:

x_{1}=\frac{-1б 4.58}{2} = 3.58\\\\x_{2}=\frac{-1б -4.58}{2} =-5.58

Step-by-step explanation:

Hello

In elementary algebra, the quadratic formula is the solution of the quadratic equation.

let a polynom

ax^{2} +bx+c=0

this can be solved d by using the quadratic equation formula

x= \frac{-bб \sqrt{b^{2}-4ac } }{2a}

Let

x^{2} =5-x

Step 1

do the equation=0

x^{2} =5-x\\x^{2}+x-5=0

define

a=1\\b=1\\c=-5\\

Sep two

put the values into the equation

x= \frac{-bб \sqrt{b^{2}-4ac } }{2a}\\\\\\x= \frac{-(1)б \sqrt{(1)^{2}-4(1)(-5) } }{2*1}\\x= \frac{-1б \sqrt{1+20 } }{2}\\x= \frac{-1б 4.58}{2}\\\\x_{1}=\frac{-1б 4.58}{2} = 3.58\\\\x_{2}=\frac{-1б -4.58}{2} =-5.58\\\\

Have a good day.

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Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i
lana66690 [7]

In the x,y plane, we have z=0 everywhere. So in the equation of the sphere, we have

25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2

which is a circle centered at (2, -10, 0) of radius 4.

In the x,z plane, we have y=0, which gives

25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the y,z plane, x=0, so

25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2

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Read 2 more answers
Which equation, when solved results in a different value of x than the other three?
Talja [164]

Answer:

-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})

Step-by-step explanation:

<u><em>The complete question in the attached figure</em></u>

<em>Verify each case</em>

Part 1) we have

-\frac{7}{8}x-\frac{3}{4}=20

solve for x

\frac{7}{8}x=-\frac{3}{4}-20

\frac{7}{8}x=-\frac{83}{4}

x=-\frac{83}{4}(\frac{8}{7})

x=-\frac{166}{7}

Part 2) we have

\frac{3}{4}+\frac{7}{8}x=-20

Multiply both sides by -1 and rearrange the terms on the left side to get

-\frac{7}{8}x-\frac{3}{4}=20

This expression is the same that the expression in Part 1)

That means, that the equations Part 1) and Part 2) are equivalent

therefore

x=-\frac{166}{7}

Part 3) we have

-7(\frac{1}{8})x-\frac{3}{4}=20

Remember that

-7(\frac{1}{8})x=-\frac{7}{8}x

This expression is the same that the expression in Part 1)

That means, that the equations Part 1) and Part 3) are equivalent

therefore

x=-\frac{166}{7}

Part 4) we have

-\frac{7}{8}(-\frac{8}{7})x-\frac{3}{4}=20(-\frac{8}{7})

This equation is not equivalent to the other three, because some terms are multiplied by -8/7 and others are not. When different things are done on either side of the equal sign, it changes the equation, resulting in a different solution

6 0
3 years ago
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