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poizon [28]
3 years ago
12

Find g−1(x) when g(x)=3/5x−9.

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

−(2x)/(5)−9

Step-by-step explanation:

Replace the function designators in g−1x

with the actual functions.

(3/5x−9)−1x

Simplify (3/5x−9)−1x

−(2x)/(5)−9

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If f(x) has an inverse on [a, b], then integrating by parts (take u = f(x) and dv = dx), we can show

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