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poizon [28]
3 years ago
12

Find g−1(x) when g(x)=3/5x−9.

Mathematics
1 answer:
weqwewe [10]3 years ago
5 0

Answer:

−(2x)/(5)−9

Step-by-step explanation:

Replace the function designators in g−1x

with the actual functions.

(3/5x−9)−1x

Simplify (3/5x−9)−1x

−(2x)/(5)−9

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GEOMETRY <br> please Help
geniusboy [140]

Answer:

A right circular cone

Step-by-step explanation:

7 0
2 years ago
I’m not sure how to slove this problem it’s a equilateral triangle and I’m trying to find out what the side is equal to.
Lerok [7]

Answer:

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Step-by-step explanation:

Because it is a equilateral triangle, it means all sides have the same length.

AB = AC

5/4 y - 1 = 7/3 y - 2

5/4 y - 7/3 y = -2 +1

-13/12 y = -1

y = 12/13

input y to the equation.

AB = 5/4 y - 1  = 5/4 (12/13) -1 = 2/13

AC= 7/3 y - 2 = 7/3 (12/13) -2 = 2/13

Please check my other articles in my site, just copy and paste this word to google search engine: learningandassignments diy4pro.

Hope it helps you.

6 0
3 years ago
Will give brainlist
kicyunya [14]

Answer:

second answer

Step-by-step explanation:

yards is commonly used for large sparse area measurements

8 0
3 years ago
How many outer atoms and lone pairs are present in a molecule with a square pyramidal shape?
arlik [135]

Answer:

5 Outer and 1 lone pair

Step-by-step explanation:

A square pyramidal shape results when one of the bonds of an octahedron structure is occupied by a lone pair.

Hence there are 5 bonded atoms and one lone pair. The hybridization about the central atom is sp^{3} d^2.

One of the most common example is Xenon tetraflouride. XeF_4. Looking at its structure we can see that it has 5 pairs of outer atoms and one lone pair. With its coordination number 5. The shape of the orbitals is octahedral.

4 0
3 years ago
Which pair of rectangles is similar ? A 3,8 and 2,6
ipn [44]
D because they are equal the same if you do 3×6=18 and 2×9=18
They have the same area amount.
~JZ
Hope it helps
4 0
2 years ago
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