All categories

3 years ago

Based on given information for each of the following, which lines cannot be parallel? f m∠1=123°, m∠8=132°

Mathematics

1 answer:

Rudiy273 years ago

5 0

Answer:

do you have a picture?

Step-by-step explanation:

I can't go off of just that (not enough info)

You might be interested in

The temperature drops 17° to 37° . what was the temperature when we started?

Alex Ar [27]

The temperature would be about 54.

3 0

3 years ago

Read 2 more answers

Let the positive numbers a, b, c. Prove that <img src="https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7B2013%7D%2Bb%5E%7B2013%7D%2Bc%5E%

Serggg [28]

Answer:

I don't need to prove it, I already believe you

7 0

2 years ago

-1/3x+2x=3 3/4 what does the variable represent?

svet-max [94.6K]

Start off by combining like terms on the LHS (the terms with x in them).

So we get $\frac{-1}{3}x+2x= \frac{-1}{3}x+ \frac{6}{3}x= \frac{-5}{3}x$

Replacing this result with what we had before on the LHS, we get $\frac{-5}{3}x=3 \frac{3}{4}= \frac{9}{4}$

⇒Solve for x (divide both sides $\frac{-5}{3}$ )
⇒Don't forget about reciprocity rules when dividing. This is the same as multiplying both sides by $\frac{3}{-5}$

⇒ $x= \frac{9}{4}( \frac{3}{-5})
$
⇒ $x= -\frac{27}{20}=-1\frac{7}{20}$ ***This is a proper fraction

4 0

3 years ago

Read 2 more answers

Five times the difference of a number and twelve is greater than forty.

Naya [18.7K]

Answer:

This is the value in numbers.

5(n-12)>40

Step-by-step explanation:

Let's solve your inequality step-by-step.

5(n−12)>40

Step 1: Simplify both sides of the inequality.

5n−60>40

Step 2: Add 60 to both sides.

5n−60+60>40+60

5n>100

Step 3: Divide both sides by 5.

100

n>20

Answer:

n>20

6 0

2 years ago

Read 2 more answers

A coin is flipped 10 times where each flip comes up either heads or tails. How many possible outcomes (a) contain exactly two he

Tems11 [23]

Answer:

a. 45

b. 176

c. 252

Step-by-step explanation:

First take into account the concept of combination and permutation:

In the permutation the order is important and it is signed as follows:

P (n, r) = n! / (n - r)!

In the combination the order is NOT important and is signed as follows:

C (n, r) = n! / r! (n - r)!

Now, to start with part a, which corresponds to a combination because the order here is not important. Thus

n = 10

r = 2

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

There are 45 possible scenarios.

Part b, would also be a combination, defined as follows

n = 10

r <= 3

Therefore, several cases must be made:

C (10, 0) = 10! / 0! * (10-0)! = 10! / (0! * 10!) = 1

C (10, 1) = 10! / 1! * (10-1)! = 10! / (1! * 9!) = 10

C (10, 2) = 10! / 2! * (10-2)! = 10! / (2! * 8!) = 45

C (10, 3) = 10! / 3! * (10-3)! = 10! / (2! * 7!) = 120

The sum of all these scenarios would give us the number of possible total scenarios:

1 + 10 + 45 + 120 = 176 possible total scenarios.

part c, also corresponds to a combination, and to be equal it must be divided by two since the coin is thrown 10 times, it would be 10/2 = 5, that is our r = 5

Knowing this, the combination formula is applied:

C (10, 5) = 10! / 5! * (10-5)! = 10! / (2! * 5!) = 252

252 possible scenarios to be the same amount of heads and tails.

6 0

3 years ago