Answer:
f'(x) = cos(3x^2)(6x)
Step-by-step explanation:
(d/dx)(sin u) = cos(u)·du/dx . . . . . chain rule
For f(x) = sin(3x^2), this means ...
0.55
-24 = 3x + 9
-24 - 9 = 3x
-33 = 3x
-33/3 = x
-11 = x
x = -11
