Question

Find f ′(x) for f(x) = sin (3x2).

Answer 1

Answer:

  f'(x) = cos(3x^2)(6x)

Step-by-step explanation:

(d/dx)(sin u) = cos(u)·du/dx . . . . . chain rule

For f(x) = sin(3x^2), this means ...

  f'(x) = cos(3x^2)(6x)