Find f ′(x) for f(x) = sin (3x2).
1 answer:
Answer:
f'(x) = cos(3x^2)(6x)
Step-by-step explanation:
(d/dx)(sin u) = cos(u)·du/dx . . . . . chain rule
For f(x) = sin(3x^2), this means ...
f'(x) = cos(3x^2)(6x)
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